2.7-5. Flaws in a certain type of drapery material appear on the average of one in 150 square feet. If we assume a Poisson distribution, find the probability of at most one flaw appearing in 225 square feet.
2.7-5. Flaws in a certain type of drapery material appear on the average of one in 150 square feet. If we assume a Poisson distribution, find the probability of at most one flaw appearing in 225 square feet.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:**Problem 2.7-5: Understanding Poisson Distribution for Material Flaws**
In a specific type of drapery material, flaws occur on average at a rate of one flaw per 150 square feet. Assume a Poisson distribution is applicable to model this scenario. Calculate the probability of encountering at most one flaw within an area of 225 square feet.
This problem involves using the Poisson distribution to determine the likelihood of a certain number of events (in this case, flaws) occurring within a fixed interval (225 square feet) based on a known average rate (one flaw per 150 square feet).
Expert Solution
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Step 1: Information given is
Flaws in a certain type of drapery material appear on the average of 1 in 150 square feet
For 1 square feet
= flaws in 1 square feet
For 225 square feet
=
=1.5 Flaws in 225 square feet
Step by step
Solved in 3 steps with 8 images
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