2.7-10. The mean of a Poisson random variable X is μ = 9. Compute P(μ – 2o < Χ < μ + 26).

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**Exercise 2.7-10**: The mean of a Poisson random variable \( X \) is \( \mu = 9 \). Compute

\[ P(\mu - 2\sigma < X < \mu + 2\sigma). \]

This exercise requires you to calculate the probability that a Poisson-distributed random variable falls within two standard deviations from the mean. The Poisson distribution is typically used to model the number of times an event occurs within a specified interval.

### Explanation:
- **Poisson Distribution**: The Poisson distribution is defined by its mean \( \mu \), which for this exercise is 9.
- **Standard Deviation**: The standard deviation \( \sigma \) for a Poisson distribution is the square root of the mean (\( \sigma = \sqrt{\mu} \)).
- **Calculation**:
  - First, compute the standard deviation: \( \sigma = \sqrt{9} = 3 \).
  - Determine the range around the mean: \( \mu - 2\sigma = 9 - 6 = 3 \) and \( \mu + 2\sigma = 9 + 6 = 15 \).
  - The problem asks for the probability that the value of \( X \) is between 3 and 15.

Using this information and relevant statistical tables or software, you can find the specific probability for this range.
Transcribed Image Text:**Exercise 2.7-10**: The mean of a Poisson random variable \( X \) is \( \mu = 9 \). Compute \[ P(\mu - 2\sigma < X < \mu + 2\sigma). \] This exercise requires you to calculate the probability that a Poisson-distributed random variable falls within two standard deviations from the mean. The Poisson distribution is typically used to model the number of times an event occurs within a specified interval. ### Explanation: - **Poisson Distribution**: The Poisson distribution is defined by its mean \( \mu \), which for this exercise is 9. - **Standard Deviation**: The standard deviation \( \sigma \) for a Poisson distribution is the square root of the mean (\( \sigma = \sqrt{\mu} \)). - **Calculation**: - First, compute the standard deviation: \( \sigma = \sqrt{9} = 3 \). - Determine the range around the mean: \( \mu - 2\sigma = 9 - 6 = 3 \) and \( \mu + 2\sigma = 9 + 6 = 15 \). - The problem asks for the probability that the value of \( X \) is between 3 and 15. Using this information and relevant statistical tables or software, you can find the specific probability for this range.
Expert Solution
Step 1: Given Information:

The mean of a Poisson random variable X is mu equals 9.

The objective is to compute P open parentheses mu minus 2 sigma less than X less than mu plus 2 sigma close parentheses

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