2.6-2. Given the difference equation (* + 2) - (* + 1) + 3(k) = e(k) where y(0) = y(1) = 0, e(0) = 0, and e(k)= 1, k = 1,2,.... (a) Solve for y(k) as a function of k, and give the numerical values of y(k), (b) Solve the difference equation directly for y(k), 0 ks 4, to verify (c) Repeat parts (a) and (b) for e(k)=0 for all k. and y(0) = 1, y(1) = -2. the results 0 sks≤ 4. of part (a).

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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2.6-2.
Given the difference equation
-
2) = 3(k+ 1) + x(k)=
y(k + 2)
where y(0) = y(1) = 0, e(0) = 0, and e(k) = 1. k=1,2,...
(a) Solve for y(k) as a function of k, and give the numerical values of y(k),
(b) Solve the difference equation directly for y(k), 0 k 4. to verify
(c) Repeat parts (a) and (b) for e(k)= 0 for all k, and y(0) = 1, y(1) = -2.
the results
0 sks
4.
of part (a).
y (k)
Transcribed Image Text:2.6-2. Given the difference equation - 2) = 3(k+ 1) + x(k)= y(k + 2) where y(0) = y(1) = 0, e(0) = 0, and e(k) = 1. k=1,2,... (a) Solve for y(k) as a function of k, and give the numerical values of y(k), (b) Solve the difference equation directly for y(k), 0 k 4. to verify (c) Repeat parts (a) and (b) for e(k)= 0 for all k, and y(0) = 1, y(1) = -2. the results 0 sks 4. of part (a). y (k)
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