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2.30 A closed system consisting of 14.5 lb of air undergoes a polytropic process from p₁ = 80 lbf/in.2, v₁ = 4 ft³/lb to a final state where p2 = 20 lbf/in.², v₂ = 11 ft³/lb. Determine the amount of energy transfer by work, in Btu, for the process. 0.09 kg p1 = 138 kPA v1 = 0.72 m3/kg p2 = 552 kPa v2 = 0.25 m3/kg

2.30 A closed system consisting of 14.5 lb of air undergoes a polytropic process from p₁ = 80 lbf/in.2, v₁ = 4 ft³/lb to a final state where p2 = 20 lbf/in.², v₂ = 11 ft³/lb. Determine the amount of energy transfer by work, in Btu, for the process. 0.09 kg p1 = 138 kPA v1 = 0.72 m3/kg p2 = 552 kPa v2 = 0.25 m3/kg

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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2.30 A closed system consisting of 14.5 lb of air undergoes a polytropic process from p1 = 80 lbf/in., vị = 4 ft/lb to a final state where p2 = 20 lbf/in.?, vz = the amount of energy transfer by work, in Btu, for the %3D 11 ft/lb. Determine process. 0.09 kg p1 = 138 kPA v1 = 0.72 m3/kg p2 = 552 kPa v2 = 0.25 m3/kg
Transcribed Image Text:2.30 A closed system consisting of 14.5 lb of air undergoes a polytropic process from p1 = 80 lbf/in., vị = 4 ft/lb to a final state where p2 = 20 lbf/in.?, vz = the amount of energy transfer by work, in Btu, for the %3D 11 ft/lb. Determine process. 0.09 kg p1 = 138 kPA v1 = 0.72 m3/kg p2 = 552 kPa v2 = 0.25 m3/kg
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