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2.3-6 Evaluate the following integrals: 1p(1 – 1)8(1)8 S (B) (b) S 8(t)g(1 – t)dt (c) 8(1)e¬ja dt (d) S, 8(1 – 2) sin at dt (h) (e) L 8(3 + t)e-' dt (f) 2(3 + 4)8(1 – 1)d: (g) 8 (2 – t)8(3 – 1) dt S elt-1) cos (x – 5)8(2x – 3) dx 0- Hint: 6(x) is located at x = 0. For example, 8(1 - ) is located at 1-: = 0; that is, at I = 1, So on.

2.3-6 Evaluate the following integrals: 1p(1 – 1)8(1)8 S (B) (b) S 8(t)g(1 – t)dt (c) 8(1)e¬ja dt (d) S, 8(1 – 2) sin at dt (h) (e) L 8(3 + t)e-' dt (f) 2(3 + 4)8(1 – 1)d: (g) 8 (2 – t)8(3 – 1) dt S elt-1) cos (x – 5)8(2x – 3) dx 0- Hint: 6(x) is located at x = 0. For example, 8(1 - ) is located at 1-: = 0; that is, at I = 1, So on.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Plz solve its h (last)part in detail

2.3-6 Evaluate the following integrals: (e) 8(3 + :)e-' dt (f) [2(1} +4)8(1 – t) dt (g) S 3 (2 – t)8(3 – t) dt s elt-1) cos 4ix – 5)8(2x – 3) dx (a) 8(t)8(1 – t) dr (b) S 8(7)g(1 – t)dt (c) dit)e¬jui dt (d) So, 8(1 – 2) sin 7t dt (h) 0- Hint: 6(x) is located at x = 0. For example, 8(1 – t) is located at 1-: = 0; that is, at i = 1, a so on.
Transcribed Image Text:2.3-6 Evaluate the following integrals: (e) 8(3 + :)e-' dt (f) [2(1} +4)8(1 – t) dt (g) S 3 (2 – t)8(3 – t) dt s elt-1) cos 4ix – 5)8(2x – 3) dx (a) 8(t)8(1 – t) dr (b) S 8(7)g(1 – t)dt (c) dit)e¬jui dt (d) So, 8(1 – 2) sin 7t dt (h) 0- Hint: 6(x) is located at x = 0. For example, 8(1 – t) is located at 1-: = 0; that is, at i = 1, a so on.
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