2.28. The following empirical equation correlates the values of variables in a system in which solid particles are suspended in a flowing gas: 1/3 1/2 kądpy (dpup\ 2.00 + 0.600 D Problems 35 Both (ulpD) and (dpuplµ) are dimensionless groups; kg is a coefficient that expresses the rate at which a particular species transfers from the gas to the solid particles; and the coefficients 2.00 and 0.600 are dimensionless constants obtained by fitting experimental data covering a wide range of values of the equation variables. The value of kg is needed to design a catalytic reactor. Since this coefficient is difficult to determine directly, values of the other variables are measured or estimated and k, is calculated from the given correlation. The variable values are as follows: d, = 5.00 mm y = 0.100 (dimensionless) D = 0.100 cm?/s H = 1.00 x 10-5 N•s/m? p = 1.00 x 10-3 g/cm³ u = 10.0 m/s (a) What is the estimated value of kg? (Give its value and units.) (b) Why might the true value of kg in the reactor be significantly different from the value estimated in Part (a)? (Give several possible reasons.) (c) Create a spreadsheet in which up to five sets of values of the given variables (d, through u) are entered in columns and the corresponding values of kg are calculated. Test your program using the following variable sets: (i) the values given above; (ii) as above, only double the particle diameter d, (making it 10.00 mm); (iii) as above, only double the diffusivity D; (iv) as above, only double the viscosity u; (v) as above, only double the velocity u. Report all five calculated values of kg.
2.28. The following empirical equation correlates the values of variables in a system in which solid particles are suspended in a flowing gas: 1/3 1/2 kądpy (dpup\ 2.00 + 0.600 D Problems 35 Both (ulpD) and (dpuplµ) are dimensionless groups; kg is a coefficient that expresses the rate at which a particular species transfers from the gas to the solid particles; and the coefficients 2.00 and 0.600 are dimensionless constants obtained by fitting experimental data covering a wide range of values of the equation variables. The value of kg is needed to design a catalytic reactor. Since this coefficient is difficult to determine directly, values of the other variables are measured or estimated and k, is calculated from the given correlation. The variable values are as follows: d, = 5.00 mm y = 0.100 (dimensionless) D = 0.100 cm?/s H = 1.00 x 10-5 N•s/m? p = 1.00 x 10-3 g/cm³ u = 10.0 m/s (a) What is the estimated value of kg? (Give its value and units.) (b) Why might the true value of kg in the reactor be significantly different from the value estimated in Part (a)? (Give several possible reasons.) (c) Create a spreadsheet in which up to five sets of values of the given variables (d, through u) are entered in columns and the corresponding values of kg are calculated. Test your program using the following variable sets: (i) the values given above; (ii) as above, only double the particle diameter d, (making it 10.00 mm); (iii) as above, only double the diffusivity D; (iv) as above, only double the viscosity u; (v) as above, only double the velocity u. Report all five calculated values of kg.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
Transcribed Image Text:2.28. The following empirical equation correlates the values of variables in a system in which solid particles
are suspended in a flowing gas:
1/3
1/2
kądpy
(dpup\
2.00 + 0.600
D
Problems 35
Both (ulpD) and (dpuplµ) are dimensionless groups; kg is a coefficient that expresses the rate at which a
particular species transfers from the gas to the solid particles; and the coefficients 2.00 and 0.600 are
dimensionless constants obtained by fitting experimental data covering a wide range of values of the
equation variables.
The value of kg is needed to design a catalytic reactor. Since this coefficient is difficult to
determine directly, values of the other variables are measured or estimated and k, is calculated from the
given correlation. The variable values are as follows:
d, = 5.00 mm
y = 0.100 (dimensionless)
D = 0.100 cm?/s
H = 1.00 x 10-5 N•s/m?
p = 1.00 x 10-3 g/cm³
u = 10.0 m/s
(a) What is the estimated value of kg? (Give its value and units.)
(b) Why might the true value of kg in the reactor be significantly different from the value estimated in
Part (a)? (Give several possible reasons.)
(c) Create a spreadsheet in which up to five sets of values of the given variables (d, through u) are
entered in columns and the corresponding values of kg are calculated. Test your program using the
following variable sets: (i) the values given above; (ii) as above, only double the particle diameter
d, (making it 10.00 mm); (iii) as above, only double the diffusivity D; (iv) as above, only double
the viscosity u; (v) as above, only double the velocity u. Report all five calculated values of kg.
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