Homework Help is Here – Start Your Trial Now!
Engineering
Chemical Engineering
How did he obtain the differential area of flow as dA= Wdy ?

How did he obtain the differential area of flow as dA= Wdy ?

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
See similar textbooks
icon
Related questions
Question
How did he obtain the differential area of flow as dA= Wdy ?
$ 4 Example-1.1: Calculation of flow rate using velocity distribution in an open channel flow R A liquid flows through an open channel as shown in the figure below. The variation of velocity in the vertical direction (v) can be expressed by: x = 2y12, Calculate the volumetric flow rate and the average velocity in the channel? Solution: The total flow rate is given by Eq. (1.3): % Atotal W=1.5 m and Y= 1.2 m 5 The average velocity is given by Eq. (1.4), Q Atotal 2.63 1.5x1.2 V = F6 Q = fundA dA = Wdy The differential area of flow for the above geometry is: Replacing dA by Wdy and ux by 2y¹2 in Eq. (1.3), and putting the limits of integration, Q=²2y¹/2 Wdy 6 → V = →Q= F7 & 7 Atotal = 1.46 W F8 8 m s F9 →>>> Q2.63 m³s-1 61 Ux=2 9 2¹/2 Ux(y) E F10 O. F11 (1.4) 0 F12
Transcribed Image Text:$ 4 Example-1.1: Calculation of flow rate using velocity distribution in an open channel flow R A liquid flows through an open channel as shown in the figure below. The variation of velocity in the vertical direction (v) can be expressed by: x = 2y12, Calculate the volumetric flow rate and the average velocity in the channel? Solution: The total flow rate is given by Eq. (1.3): % Atotal W=1.5 m and Y= 1.2 m 5 The average velocity is given by Eq. (1.4), Q Atotal 2.63 1.5x1.2 V = F6 Q = fundA dA = Wdy The differential area of flow for the above geometry is: Replacing dA by Wdy and ux by 2y¹2 in Eq. (1.3), and putting the limits of integration, Q=²2y¹/2 Wdy 6 → V = →Q= F7 & 7 Atotal = 1.46 W F8 8 m s F9 →>>> Q2.63 m³s-1 61 Ux=2 9 2¹/2 Ux(y) E F10 O. F11 (1.4) 0 F12
Expert Solution
steps

Step by step

Solved in 3 steps with 9 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Introduction to Chemical Engineering Thermodynami…
Introduction to Chemical Engineering Thermodynami…
Chemical Engineering
ISBN:
9781259696527
Author:
J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:
McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemical Engineering
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
Elements of Chemical Reaction Engineering (5th Ed…
Elements of Chemical Reaction Engineering (5th Ed…
Chemical Engineering
ISBN:
9780133887518
Author:
H. Scott Fogler
Publisher:
Prentice Hall
Process Dynamics and Control, 4e
Process Dynamics and Control, 4e
Chemical Engineering
ISBN:
9781119285915
Author:
Seborg
Publisher:
WILEY
Industrial Plastics: Theory and Applications
Industrial Plastics: Theory and Applications
Chemical Engineering
ISBN:
9781285061238
Author:
Lokensgard, Erik
Publisher:
Delmar Cengage Learning
Unit Operations of Chemical Engineering
Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:
9780072848236
Author:
Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:
McGraw-Hill Companies, The
SEE MORE TEXTBOOKS