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• 2.2 Gibbs paradox (a) Suppose that 1 N(E) = d3N pd3Nq h3N ESH IS correct. Consider two volumes asEtSE = V of ideal gas, each E VB containing N identical particles with the same mean energy. Show that if the two systems are joined together, SA+B = SA + SB + 2NKB In 2 that is, there is an entropy of mixing 2NKB In 2. (b) Show that if the correct expression is used, SA+B = SA + SB

• 2.2 Gibbs paradox (a) Suppose that 1 N(E) = d3N pd3Nq h3N ESH IS correct. Consider two volumes asEtSE = V of ideal gas, each E VB containing N identical particles with the same mean energy. Show that if the two systems are joined together, SA+B = SA + SB + 2NKB In 2 that is, there is an entropy of mixing 2NKB In 2. (b) Show that if the correct expression is used, SA+B = SA + SB

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• 2.2 Gibbs paradox (a) Suppose that 1 Ω(Ε)- d³Npd3Nq h3N JESHGSE+&E_ V of ideal gas, each E<H t8E is correct. Consider two volumes V=VE = V of ideal gas, each %D A B containing N identical particles with the same mean energy. Show that if the two systems are joined together, SA+B = SA + SB + 2NKB In 2 that is, there is an entropy of mixing 2NKB In 2. %3D (b) Show that if the correct expression is used, SA+B = SA + SB %3D
Transcribed Image Text:• 2.2 Gibbs paradox (a) Suppose that 1 Ω(Ε)- d³Npd3Nq h3N JESHGSE+&E_ V of ideal gas, each E<H t8E is correct. Consider two volumes V=VE = V of ideal gas, each %D A B containing N identical particles with the same mean energy. Show that if the two systems are joined together, SA+B = SA + SB + 2NKB In 2 that is, there is an entropy of mixing 2NKB In 2. %3D (b) Show that if the correct expression is used, SA+B = SA + SB %3D
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