• 2.2 Gibbs paradox (a) Suppose that 1 N(E) = d3N pd3Nq h3N ESH IS correct. Consider two volumes asEtSE = V of ideal gas, each E VB containing N identical particles with the same mean energy. Show that if the two systems are joined together, SA+B = SA + SB + 2NKB In 2 that is, there is an entropy of mixing 2NKB In 2. (b) Show that if the correct expression is used, SA+B = SA + SB
• 2.2 Gibbs paradox (a) Suppose that 1 N(E) = d3N pd3Nq h3N ESH IS correct. Consider two volumes asEtSE = V of ideal gas, each E VB containing N identical particles with the same mean energy. Show that if the two systems are joined together, SA+B = SA + SB + 2NKB In 2 that is, there is an entropy of mixing 2NKB In 2. (b) Show that if the correct expression is used, SA+B = SA + SB
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(a) Suppose that
1
Ω(Ε)-
d³Npd3Nq
h3N
JESHGSE+&E_ V of ideal gas, each
E<H
t8E
is correct. Consider two volumes V=VE = V of ideal gas, each
%D
A
B
containing N identical particles with the same mean energy. Show that if
the two systems are joined together,
SA+B = SA + SB + 2NKB In 2
that is, there is an entropy of mixing 2NKB In 2.
%3D
(b) Show that if the correct expression is used,
SA+B = SA + SB
%3D"
Transcribed Image Text:• 2.2 Gibbs paradox
(a) Suppose that
1
Ω(Ε)-
d³Npd3Nq
h3N
JESHGSE+&E_ V of ideal gas, each
E<H
t8E
is correct. Consider two volumes V=VE = V of ideal gas, each
%D
A
B
containing N identical particles with the same mean energy. Show that if
the two systems are joined together,
SA+B = SA + SB + 2NKB In 2
that is, there is an entropy of mixing 2NKB In 2.
%3D
(b) Show that if the correct expression is used,
SA+B = SA + SB
%3D
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