Answered: 2. Zn(s) | Zn²+ (0.05 M) || Zn²+ (1 M)…

2. Zn(s) | Zn²+ (0.05 M) || Zn²+ (1 M) | Zn(s) Calculation for E (cal.) (eq. 11): E = 0.0592 K: lowere concentreation Y= highert concentreation

Chemistry for Engineering Students

3rd Edition

ISBN:9781285199023

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter1: Introduction To Chemistry

Section: Chapter Questions

Problem 1.77PAE

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Question

2. Zn(s) | Zn²+ (0.05 M) || Zn²+ (1 M) | Zn(s)
Calculation for E (cal.) (eq. 11): E =
0.0592
K: lowere concentreation
Y= highert concentreation

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