### Topic: Writing Balanced Chemical Equations#### Problem Statement:Write balanced equations, assuming all ionic compounds are dissolved in water. Include the states of all reactants and products.#### Exercises:a) **Cobalt (II) Chloride reacts with hydrofluoric acid**- **Solution**: To write the balanced chemical equation, identify the reactants and products, and balance the number of atoms for each element. Specify the states of the compounds (aqueous or solid).b) **Solid sodium bicarbonate decomposes into solid sodium carbonate, carbon dioxide, and water**- **Solution**: The decomposition of sodium bicarbonate involves breaking it down into simpler compounds. Write the balanced equation and indicate the states: sodium bicarbonate (solid), sodium carbonate (solid), carbon dioxide (gas), and water (liquid).c) **Lead (II) acetate reacts with potassium chloride**- **Solution**: For this reaction, identify the products formed and ensure the equation is balanced by having the same number of each type of atom on both sides. Include the states, typically aqueous for the reactants and either solid or aqueous for the products.#### Note:- Balance the equations by adjusting coefficients, never by changing subscripts in the chemical formulas.- Use the solubility rules to determine the states of the products formed in these reactions.

We need to write the balanced chemical reaction of the given reactants and reaction conditions. a) Cobalt (II) chloride react with hydrofluoric acid. 1 mole of aqueous Cobalt (II) Chloride [CoCl2] reacts with 2 moles of aqueous Hydrofluoric Acid [HF] to form 1 mole of aqueous Cobalt(Ii) Fluoride [CoF2] and 2 moles of aqueous Hydrogen Chloride [HCl]. This is a double displacement reaction. So the balanced reaction is, CoCl2(aq) + 2HF (aq) -------> CoF2 (aq) + 2HCl (aq)b) solid sodium bicarbonate decomposed into solid sodium carbonate, carbon dioxide and water. This is a decomposition reaction and the balanced chemical reaction can be written as, 2NaHCO3 (s) -----> Na2CO3 (s) + H2O (l) + CO2 (g)c) Lead (II) acetate reacts with potassium chloride. 1 mole of aqueous Lead(II) Acetate [Pb(CH3COO)2] reacts with 2 moles of aqueous Potassium Chloride [KCl] to form 2 moles of aqueous Potassium Acetate [KCH3COO] and 1 mole of solid Cotunnite [PbCl2] Pb(CH3COO)2 (aq) + 2KCl (aq) ------> 2CH3COOK (aq) + PbCl2 (s)

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2. Write balanced equations, assume all ionic compounds are dissolved in water. Include states of all reactants and products. a) Cobalt (II) Chloride reacts with hydrofluoric acid b) Solid sodium bicarbonate decomposes into solid sodium carbonate, carbon dioxide and water. c) Lead (II) acetate reacts with potassium chloride.

2. Write balanced equations, assume all ionic compounds are dissolved in water. Include states of all reactants and products. a) Cobalt (II) Chloride reacts with hydrofluoric acid b) Solid sodium bicarbonate decomposes into solid sodium carbonate, carbon dioxide and water. c) Lead (II) acetate reacts with potassium chloride.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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