2. Work out the Chi-Squared Goodness of Fit for Mendel's actual data on flower position: "Expt. 6: Position of flowers. Among 858 cases 651 had inflorescences axial and 207 terminal. Ratio, 3.14:1." F2: # terminal # axial sums: O 207 651 858 degrees of freedom Chi-squared value p-value: E 214.5 643.5 O-E -7.5 7.5 (0-E)^2 56.25 (0-E) ^2/E 0.2622377
2. Work out the Chi-Squared Goodness of Fit for Mendel's actual data on flower position: "Expt. 6: Position of flowers. Among 858 cases 651 had inflorescences axial and 207 terminal. Ratio, 3.14:1." F2: # terminal # axial sums: O 207 651 858 degrees of freedom Chi-squared value p-value: E 214.5 643.5 O-E -7.5 7.5 (0-E)^2 56.25 (0-E) ^2/E 0.2622377
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Can you help me solve these problems. The first one I belive I did wrong. I am having trouble mostly wit identifying the expected numbers. Please help me figure out the expected numbers.
Transcribed Image Text:2. Work out the Chi-Squared Goodness of Fit for Mendel's actual
data on flower position:
"Expt. 6: Position of flowers. Among 858 cases 651 had.
inflorescences axial and 207 terminal. Ratio, 3.14:1."
F2:
#terminal
#axial
sums:
degrees of freedom
Chi-squared value =
p-value:
F2:
O
#yellow pod
# green pod
207
651
858
sums:
p-value:
E
degrees of freedom
Chi-squared value
214.5
643.5
O-E
-7.5
3. Work out the Chi-Squared Goodness of Fit for Mendel's actual
data:
7.5
< p <
Expt. 5: Color of the unripe pods. The number of trial plants.
was 580, of which 428 had green pods and 152 yellow ones.
Consequently these stand in the ratio of 2.82:1.
OE
(O-E) ^2
56.25
O-E
(0-E)^2/E
0.2622377
(0-E) ^2
(0-E) ^2/E
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