### Statistical Analysis of Lyme Disease Ticks in Deer PopulationIn a study conducted by wildlife biologists, a sample of 153 deer, taken by hunters, was inspected. Among these deer, 32 were found to be carrying Lyme disease ticks. The following questions guide the statistical analysis of the sample data:**2. Wildlife biologists inspect 153 deer taken by hunters and find 32 of them carrying Lyme disease ticks.****a) Calculate the standard error of the sample proportion.**The standard error (SE) of the sample proportion can be calculated using the formula:\[ SE = \sqrt{\frac{p(1-p)}{n}} \]where $ p $ is the sample proportion and $ n $ is the sample size.**b) Calculate the margin of error with a confidence level of 98%.**The margin of error (ME) can be found using the formula:\[ ME = Z \times SE \]where $ Z $ is the Z-score corresponding to the 98% confidence level, which is typically 2.33 for 98%.**c) Determine the 98% confidence interval for the proportion of deer that carry Lyme disease ticks. Interpret.**The 98% confidence interval (CI) for the proportion can be calculated using the formula:\[ \text{CI} = \hat{p} \pm ME \]where $ \hat{p} $ is the sample proportion (in this case, 32/153).### Detailed Explanations:1. **Standard Error Calculation:** - Determine $ \hat{p} $ (sample proportion): $ \hat{p} = \frac{32}{153} $ - Plug $ \hat{p} $ and $ n $ into the SE formula to compute the standard error.2. **Margin of Error Calculation:** - Identify the Z-score for a 98% confidence level. - Use the calculated SE and Z-score to find the margin of error.3. **Confidence Interval Calculation:** - Apply the margin of error to the sample proportion to find the lower and upper bounds of the 98% confidence interval. - Interpret the interval to understand the range within which the true population proportion of deer carrying Lyme disease ticks lies with 98% confidence.By following these calculations, students and researchers can understand the prevalence of Lyme disease ticks in the deer population and make

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Description: ### Statistical Analysis of Lyme Disease Ticks in Deer PopulationIn a study conducted by wildlife biologists, a sample of 153 deer, taken by hunters, was inspected. Among these deer, 32 were found to be carrying Lyme disease ticks. The following que

Confidence interval: The (1-α) % confidence interval for proportion p is given by,

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2. Wildlife biologists inspect 153 deer taken by hunters and find 32 of them carrying Lyme disease ticks. a) Calculate the standard error of the sample proportion. I b) Calculate the margin of erTor with confidence level of 98%. c) Determine the 98% confidence interval for the proportion of deer that carry Lyme disease ticks. Interpret.

2. Wildlife biologists inspect 153 deer taken by hunters and find 32 of them carrying Lyme disease ticks. a) Calculate the standard error of the sample proportion. I b) Calculate the margin of erTor with confidence level of 98%. c) Determine the 98% confidence interval for the proportion of deer that carry Lyme disease ticks. Interpret.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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