2. Vanillin is one of the major components of the extract of vanilla beans: Vanillin This proton has a pK₂ of 7.8 Mogol H3C HO H In the structure above, all atoms are neutral but lone pairs are not explicitly drawn. Using hydroxide ion as the Bronsted base, draw a mechanism to show the deprotonation of the OH group in vanillin. Include all necessary curved arrows, lone pair electrons and nonzero formal charges. Draw the products of the proton transfer reaction. You will need to redraw the structure of vanillin.

2. Vanillin is one of the major components of the extract of vanilla beans: Vanillin This proton has a pK₂ of 7.8 Mogol H3C HO H In the structure above, all atoms are neutral but lone pairs are not explicitly drawn. Using hydroxide ion as the Bronsted base, draw a mechanism to show the deprotonation of the OH group in vanillin. Include all necessary curved arrows, lone pair electrons and nonzero formal charges. Draw the products of the proton transfer reaction. You will need to redraw the structure of vanillin.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Which letter is near the most acidic protons in the molecule below. 0000 A А H3C, of B of o CH3 D
Answer the following questions for the reaction scheme below: OH e :CEN HIC N cyanide hydrogen cyanide phenol pka <= 10.0 pka = 3.46 a. The equilibrium favors the [Select] b. This reaction is best described as a(n) [Select] c. The strongest acid in the reaction is the [Select] [Select] d. The nucleophile in the forward reaction is e. The electrophile in the reverse reaction is [Select] phenolate %. ✓ reaction. 15 <
What reagents should be used to prepare the following compound
11
From 1 being the least acidic and 4 being the most acidic, arrange the following organic compounds in terms of increasing acidity
-NH2 ج جب ON NH2 Rank the following structures in order of increasing basicity. H3CO III NH2 A) | < II < ||| B) II < I < ||| C) III < I < || D) I < III < || E) ||| < || < |
Use the information in the pK table to rank the molecules in order of decreasing basicity. For exam and "2" for the next strongest base and so on. CH3NH₂ H HSO4 HS Molecules (Choose one) (Choose one) (Choose one) (Choose one) X CH1 NH₂ H₁₂ CH,NH, H₂O CH₂OH 48 38 36 33 15.7 15.5 pk₁ table a CH,NH, CH, SH 10.4 HCN NH H₂S CH,CO,H 10.6 9.4 9.2 7.00 4.76
Hi. Please help me with ii
14) For each compound below, the most acidic proton has been starred (*). Comparing compounds A-E, which H* is the least acidic? A H* *HH* B *H C F3C *H D o= F3C O *H E CF3
The pK, values of acids A-C are 9.0, 9.1, and 9.2. Match OH ОН OH each of these values with its structure. CI Br A В
Answer questions a-c about the Bronsted acid-base reaction below using the identifying letters A-D below each structure. The pka's for the acids of interest are: ethylammonium ion (pK₂ = 10.8), and hydrogen chloride (pK₂ = -7). NH₂ A ethylamine Submit Answer + H CI B hydrogen chloride CH3 NH3 с ethylammonium + CI D chloride a) The stronger acid is b) Its conjugate base is c) The species that predominate at equilibrium are (two letters, e.g. ac) Retry Entire Group 2 more group attempts remaining
Answer questions a-c about the Bronsted acid-base reaction below using the identifying letters A-D below each structure. The pKa's for the acids of interest are: ethylammonium ion (pK = 10.8), and hydrogen chloride (pKa = -7). CH3- NH2 CH3. NH3 cī H-CI H2 A в D chloride ethylamine hydrogen chloride ethylammonium a) The stronger acid is b) Its conjugate base is c) The species that predominate at equilibrium are (two letters, e.g. ac)