2. Use Hess's law and the following set of reactions:a) N2H4 (1) + 02 (1)b) H2(g)H2 (g) + O2 (g) → H2O (1)N2 (g) +2H2O (1)AH=-622.2 kJAH=-285.8 kJAH=-187.8 kJc) H2(g) + O2 (g) → H2O2 (1)to calculate the AH for the reactionN2H4 (1)+ 2H2O2 (1)>N2 (g) + 4H2O (1)Solution:

Answered: 2. Use Hess's law and the following set…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider these reactions: Reaction 1: H2(g) + Cl2(g) 2HCI(g) AH = -184.6 kJ Reaction 2: 20F2(g)- O2(g) + 2 F2(g) AH = -49.4 kJ Reaction 3: N2(g) + 202(g) 2NO2(g) AH = +66.4 kJ Reaction 2 can be described as an [Select] [ Select ] reaction
Which of the following reactions is accompanied by an increase in enthalpy? Select one: O 2s03(g) – 2S02(g) + O2(g) A,H" = +197 kJ O 2NO(g) + O2(g) - 2NO2(g) + 113 kJ O 2H2(g) + O2(g) - 484 kJ – 2H20(g) 4HCI(g) + 02(g) - 2H20(g) + 2Cl2(g) A,H' = -111.4 kJ
2. Consider the following thermochemical equations: C(graphite) + O2 (g) → co2 (g) AH°rn = -393.5 kJ H2 (g) + % 02 (g) → H;0 (/) AHO = -285.8 kJ 2 C:Hs (g) + 702 (g) → 4 CO2 (g) + 6 H20 (1) AH°rn = -3119.6 kJ a. Derive the thermochemical equation describing the combustion of two moles of C(graphite). b. Derive the thermochemical equation describing the combustion of three moles of H2 (g). c. Derive the thermochemical equation describing the synthesis of one mole of C,Hg (9) from carbon dioxide and water. d. Use Hess's Law and the three thermochemical equations you derived in parts a-c to determine the AH°ran for the following reaction: 2C (graphite) + 3 H2 (g) → C;Hs (g)
Given the following thermochemical equations: C2H29) + 5 02(9) 2C02(g) + H201) AH° = -1229.5 kJ AH° = -393.5 kJ C(6) + 02(g) → C02(g) 1 H2(9) +5 02(9) → H20) AH° = -285.5 kJ 2 Calculate the enthalpy (in kJ) for this reaction: 206) + H2(g) → C,H2(9)
Can someone verify my answers? I got: a) endothermic b)-1149.5 J c) 1149.5 J d)0.0117 mol e) 97704.05 J/mol
Calculate AHO,xn for each of the following using data from Appendix B. (a) 2 H2S(g) + 3 02(g) → 2 SO2(g) + 2 H20(g) kJ (b) SiO2(s) + 4 HF(g) → SİF4(g) + 2 H20(/) kJ
Hess's Law Given the following data: 4C(s) + 3H2(g) + 1/2O2(g) → HCOC(CH2)(CH3)(l) ΔH°=-139.0 kJ CH3CH2OH(l) + 1/2O2(g) → CH3CHO(l) + H2O(l) ΔH°=-204.0 kJ 2C(s) + 3H2(g) + 1/2O2(g) → CH3CH2OH(l) ΔH°=-278.0 kJ H2(g) + 1/2O2(g) → H2O(l) ΔH°=-286.0 kJ calculate ΔH° for the reaction:2CH3CHO(l) → HCOC(CH2)(CH3)(l) + H2O(l)
（1）Consider the reaction: 2A (g) + 3 B (g) → 2 C (g) ΔHrxn = +254.3 kJ What will be the enthalpy change (in kJ) if 0.471 mol B reacts in excess A? （2）Consider the reaction: C (s) + O2 (g) → CO2 (g) ΔHrxn = -393.5 kJ What mass of carbon (in g) must be reacted via this mechanism to release 581.2 kJ of heat?
Given the following enthalpy change values for the reactions below: A + B → 2C; AH = -485.1 kJ mol-¹ C + 2D + E +F; AH = 251.4 kJ mol-¹ ½E + G +H; AH = 471.1 kJ mol-¹ Calculate A,H for the following reaction (in kJ mol-¹) using Hess's Law: A + B + 4D + 4G → 4H + 2F Answer:
How much heat in kJ is liberated at constant pressure if enough calcium carbonate reacts with 84.02 mL of 2.93 M hydrochloric acid? CaCO3(s) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g); ΔrH° = –14.2 kJ/mol-rxn Do not include unit. Keep 2 decimal places in your answer. ONLY TYPE IN THE AMOUNT. DO NOT INCLUDE THE NEGATIVE SIGN.

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2. Use Hess's law and the following set of reactions: a) N2H4 (1) + 02 (1) b) H2(g) H2 (g) + O2 (g) → H2O (1) N2 (g) + 2H2O (1) AH=-622.2 kJ AH=-285.8 kJ AH=-187.8 kJ c) H2(g) + O2 (g) → H2O2 (1) to calculate the AH for the reaction N2H4 (1) + 2H2O2 (1) >N2 (g) + 4H2O (1) Solution: