2. Two machines are running continuously, with their operating states described by two Markov chains. For each machine, the possible states are {1, 2, 3, 4, 5, 6}. The state of the first machine on day t is Xt. The state of the second machine on day t is Yt. The transition matrices for (Xo, X₁,...) and (Yo, Y₁,...) are P and Q respectively where: /1/3 2/3 0 0 0 10 0 1/3 4/9 2/9 0 0 0 0 1/3 0 1/3 1/3 P = ; 0 0 0 1/3 4/9 2/9 Q = 0 0 1 0 0 0 0 0 2/3 1/3 0 0 00 00 0 00 0 1/2 1/2 0 2/3 1/3 2/3 0 2/3 0 0 1/3 0 0 0 0 0 1/3/ 100 0 0 0 100 0 0 0 Supose that you (correctly) calculate that the vector w = (1/4 1/4 1/6 1/12 5/36 1/9) is both: ⚫ a limiting distribution for the Markov chain (Xo, X1, ...) ⚫ the unique equilibrium distribution but not a limiting distribution for the Markov chain (Yo, Y₁,...) (a) Using non-mathematical language, describe two things about the behaviour involving state 3 which apply to both machines. (b) Using non-mathematical language, describe one aspect of the behaviour of the first machine involving state 3 which does not apply to the second machine and explain the reason for this difference between the two machines.

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter2: Matrices
Section2.5: Markov Chain
Problem 47E: Explain how you can determine the steady state matrix X of an absorbing Markov chain by inspection.
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2. Two machines are running continuously, with their operating states described by
two Markov chains. For each machine, the possible states are {1, 2, 3, 4, 5, 6}. The
state of the first machine on day t is Xt. The state of the second machine on day t is
Yt. The transition matrices for (Xo, X₁,...) and (Yo, Y₁,...) are P and Q respectively
where:
/1/3 2/3 0 0 0
10
0 1/3 4/9 2/9
0
0
0
0
1/3 0
1/3
1/3
P =
;
0
0
0
1/3 4/9 2/9
Q =
0
0 1 0 0 0
0 0 2/3 1/3 0 0
00 00 0
00
0
1/2 1/2
0 2/3 1/3
2/3 0
2/3
0
0
1/3 0
0 0 0
0 1/3/
100 0 0 0
100 0 0 0
Supose that you (correctly) calculate that the vector w = (1/4 1/4 1/6 1/12 5/36 1/9)
is both:
⚫ a limiting distribution for the Markov chain (Xo, X1, ...)
⚫ the unique equilibrium distribution but not a limiting distribution for the
Markov chain (Yo, Y₁,...)
Transcribed Image Text:2. Two machines are running continuously, with their operating states described by two Markov chains. For each machine, the possible states are {1, 2, 3, 4, 5, 6}. The state of the first machine on day t is Xt. The state of the second machine on day t is Yt. The transition matrices for (Xo, X₁,...) and (Yo, Y₁,...) are P and Q respectively where: /1/3 2/3 0 0 0 10 0 1/3 4/9 2/9 0 0 0 0 1/3 0 1/3 1/3 P = ; 0 0 0 1/3 4/9 2/9 Q = 0 0 1 0 0 0 0 0 2/3 1/3 0 0 00 00 0 00 0 1/2 1/2 0 2/3 1/3 2/3 0 2/3 0 0 1/3 0 0 0 0 0 1/3/ 100 0 0 0 100 0 0 0 Supose that you (correctly) calculate that the vector w = (1/4 1/4 1/6 1/12 5/36 1/9) is both: ⚫ a limiting distribution for the Markov chain (Xo, X1, ...) ⚫ the unique equilibrium distribution but not a limiting distribution for the Markov chain (Yo, Y₁,...)
(a) Using non-mathematical language, describe two things about the behaviour
involving state 3 which apply to both machines.
(b) Using non-mathematical language, describe one aspect of the behaviour of the
first machine involving state 3 which does not apply to the second machine and
explain the reason for this difference between the two machines.
Transcribed Image Text:(a) Using non-mathematical language, describe two things about the behaviour involving state 3 which apply to both machines. (b) Using non-mathematical language, describe one aspect of the behaviour of the first machine involving state 3 which does not apply to the second machine and explain the reason for this difference between the two machines.
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