2. Toluene has a vapor pressure of 40.4 mm Hg at 4.4°C and 3166.0 mm Hg at 55.2°C. Solve for the AHvap of toluene. At what temperature will toluene have a vapor pressure of 700.0 mm Hg? goitonib

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### Problem Statement on Vapor Pressure of Toluene

**Problem 2:**

Toluene has a vapor pressure of 40.4 mm Hg at 4.4°C and 316.0 mm Hg at 52.2°C. Solve for the ΔHvap (enthalpy of vaporization) of toluene. At what temperature will toluene have a vapor pressure of 700.0 mm Hg?

---

**Explanation:**

This problem involves determining the enthalpy of vaporization (ΔHvap) for toluene using the Clausius-Clapeyron equation and subsequently solving for the temperature at which toluene will achieve a specified vapor pressure.

Ensure to follow the steps of using the Clausius-Clapeyron equation:

1. **Identify the given data:**
   - Vapor pressure (P1) = 40.4 mm Hg at T1 = 4.4°C
   - Vapor pressure (P2) = 316.0 mm Hg at T2 = 52.2°C
   - Desired vapor pressure (P3) = 700.0 mm Hg

2. **Convert temperatures from Celsius to Kelvin:**
   - T1 = 4.4 + 273.15 = 277.55 K
   - T2 = 52.2 + 273.15 = 325.35 K

3. **Use the Clausius-Clapeyron equation:**
   \[
   \ln \left( \frac{P2}{P1} \right) = \frac{\Delta H_{vap}}{R} \left( \frac{1}{T1} - \frac{1}{T2} \right)
   \]
   - Where R is the universal gas constant (8.314 J/mol·K).

4. **Rearrange the equation to solve for ΔHvap:**
   \[
   \Delta H_{vap} = \frac{ \ln \left( \frac{P2}{P1} \right) \times R }{ \left( \frac{1}{T1} - \frac{1}{T2} \right) }
   \]

5. **Once ΔHvap is determined, use it to find the new temperature (T3) for P3 using the Clausius-Clapeyron equation again:**
   \[
   \
Transcribed Image Text:### Problem Statement on Vapor Pressure of Toluene **Problem 2:** Toluene has a vapor pressure of 40.4 mm Hg at 4.4°C and 316.0 mm Hg at 52.2°C. Solve for the ΔHvap (enthalpy of vaporization) of toluene. At what temperature will toluene have a vapor pressure of 700.0 mm Hg? --- **Explanation:** This problem involves determining the enthalpy of vaporization (ΔHvap) for toluene using the Clausius-Clapeyron equation and subsequently solving for the temperature at which toluene will achieve a specified vapor pressure. Ensure to follow the steps of using the Clausius-Clapeyron equation: 1. **Identify the given data:** - Vapor pressure (P1) = 40.4 mm Hg at T1 = 4.4°C - Vapor pressure (P2) = 316.0 mm Hg at T2 = 52.2°C - Desired vapor pressure (P3) = 700.0 mm Hg 2. **Convert temperatures from Celsius to Kelvin:** - T1 = 4.4 + 273.15 = 277.55 K - T2 = 52.2 + 273.15 = 325.35 K 3. **Use the Clausius-Clapeyron equation:** \[ \ln \left( \frac{P2}{P1} \right) = \frac{\Delta H_{vap}}{R} \left( \frac{1}{T1} - \frac{1}{T2} \right) \] - Where R is the universal gas constant (8.314 J/mol·K). 4. **Rearrange the equation to solve for ΔHvap:** \[ \Delta H_{vap} = \frac{ \ln \left( \frac{P2}{P1} \right) \times R }{ \left( \frac{1}{T1} - \frac{1}{T2} \right) } \] 5. **Once ΔHvap is determined, use it to find the new temperature (T3) for P3 using the Clausius-Clapeyron equation again:** \[ \
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