2. This question studies the separation of variables method for Laplace equation after splitting the boundary conditions. Let D rectangular domain in R². Assume uz solve the following Dirichlet problem of Laplace equation {(x, y) |0 < x < a, 0 < y < b} be a Au2 = 0 U2(0, y) = u2(a, y) = 0 for 0 < y < b u2(x, 0) = h(x) uz(x, b) = k(x) in D for 0 < x < a for 0
2. This question studies the separation of variables method for Laplace equation after splitting the boundary conditions. Let D rectangular domain in R². Assume uz solve the following Dirichlet problem of Laplace equation {(x, y) |0 < x < a, 0 < y < b} be a Au2 = 0 U2(0, y) = u2(a, y) = 0 for 0 < y < b u2(x, 0) = h(x) uz(x, b) = k(x) in D for 0 < x < a for 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![2. This question studies the separation of variables method for Laplace equation after
splitting the boundary conditions. Let D =
rectangular domain in R². Assume uz solve the following Dirichlet problem of Laplace
equation
{(x, y) | 0 < x < a, 0 < y < b} be a
Au2 = 0
U2(0, y) = u2(a, y) =
uz (x, 0) = h(x)
U2(x, b) = k(x)
Show that the solution u2 has the following form
in D
0 for 0<y < b
for 0 < x < a
for 0< x < a
00
uz(7, 4) = E C, sinh () + D, sinh ( (y – b)
NTY`
sin
n=1
where
k(2) sin () d
NTX
Cn
x
a sinh (nab)
a
and
-2
/ h(x) sin
Dn =
dx
a sinh (n)
a
for n = 1,2, ...](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b0185de-0645-4c2a-aea4-e046d61ab5cb%2F668bfeb6-a9cc-47c0-aa58-2095d522a2c9%2Fz7x4pf9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2. This question studies the separation of variables method for Laplace equation after
splitting the boundary conditions. Let D =
rectangular domain in R². Assume uz solve the following Dirichlet problem of Laplace
equation
{(x, y) | 0 < x < a, 0 < y < b} be a
Au2 = 0
U2(0, y) = u2(a, y) =
uz (x, 0) = h(x)
U2(x, b) = k(x)
Show that the solution u2 has the following form
in D
0 for 0<y < b
for 0 < x < a
for 0< x < a
00
uz(7, 4) = E C, sinh () + D, sinh ( (y – b)
NTY`
sin
n=1
where
k(2) sin () d
NTX
Cn
x
a sinh (nab)
a
and
-2
/ h(x) sin
Dn =
dx
a sinh (n)
a
for n = 1,2, ...
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