2. The probabilities of events A and B are P(A) and P(B) respectively.5Р(4)1P(AN B)=7P(AU B) = q12Find, in terms of q,а. Р(В),b. P(A|B).Given that A and B are independent events,c. find the value of q.

Name: 2. The probabilities of events A and B are P(A) and P(B) respectively
Uploaded: 2024-03-20T07:06:41.000Z
Channel: Bartleby
Description: 2. The probabilities of events A and B are P(A) and P(B) respectively.5Р(4)1P(AN B)=7P(AU B) = q12Find, in terms of q,а. Р(В),b. P(A|B).Given that A and B are independent events,c. find the value of q.

It is not mentioned that the given events A and B are independent initially. For 2 events that are…

Math

Probability

2. The probabilities of events A and B are P(A) and P(B) respectively. 5 1 P(A) 12 P(AN B) =. P(AUB) = q 6 Find, in terms of q, а. Р(В), b. Р(A|B). Given that A and B are independent events, c. find the value of q.

2. The probabilities of events A and B are P(A) and P(B) respectively. 5 1 P(A) 12 P(AN B) =. P(AUB) = q 6 Find, in terms of q, а. Р(В), b. Р(A|B). Given that A and B are independent events, c. find the value of q.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: Let Ω be some basic set, P its probability distribution, and A, B ⊂ Ω events. (1) Show that if A is…

Q: When two events can't happen at the same time, we use "The Or Law" and we add the probabilities…

A: Here, probability of winning a Toaster = 14% Probability of winning washer-dryer = 6% Now, For a…

Q: 47. Suppose A and B are two events with P(A) = 0.36, P(B) = 0.48, and the P(A or B) = 0.60. (a) Find…

Q: It is known that P(AB)=0.45, P(B)=0.90 and the events A and B are independent. Find…

A: Independent events are events that do not affect the outcome of subsequent events.

Q: Use the equations above to find the missing probability. 13. Event A and Event B are independent a)…

A: 13 a) Given data,P(B)=12P(A and B)=740P(A)=? P(A and B)=P(A)*P(B) 740=P(A)*12P(A)=1440P(A)=720

Q: Find the probability of the indicated events if P(E)=0.3 , P(F)=0.4 , and P(F|E)=0.3 (a) P(E∩F)…

A: GivenP(E)=0.3P(F)=0.4P(F|E)=0.3

Q: Three contractors (call them A, B, and C) bid on a project to build an addition to Kretschmar Hall.…

A: Let PA represents the probability of winning of contractor A, PB represents the probability of…

Q: For each set of probabilities, determine whether the events A and B are independent or dependent.…

A: We have to find whether events A and B are independent or dependent in each part. Concept/Formula…

Q: 4. The probabilities for event A and B are P(A) = 0.4 and P(B) = 0.33. Find P(A U B) if a) A and B…

A: a). Given:P(A)=0.4P(B)=0.33 The formula of probability is: P(A∪B)=P(A)+P(B)-P(A∩B) As the events are…

Q: Prior Probabilities for A1 and A2: P(A1)=0.20, P(A2)=0.40, (A1) and (A2) are mutually exlcusive.…

A: Data given P(A1)=0.20, P(A2)=0.40, (B|A1)=0.20, P(B|A2)=0.05

Q: Match the probability with the calculator command.

A: binompdf(n,p,x)=P(X=x) binomcdf(n,p,x)=P(X≤x)

Q: Recall the multiplication rule for conditional probabilities given events A and B. P(ANB) = P(A)P(B…

A: According to the given information, we have P(A1)=0.80P(B|A1)=0.25P(A2)=0.20P(B|A2)=0.10

Q: When a woman goes for shopping she may buy several goods between them clothes and shoes. She has…

A: (a) Obtain the probability that in one shopping day she buys at least one of the goods “clothes”…

Q: Find P(A or B or C) for the given probabilities. P(A) = 0.35, P(B) = 0.24, P(C) = 0.14 P(A and B) =…

A: P(A) = 0.35, P(B) = 0.24, P(C) = 0.14 P(A and B) = 0.13, P(A and C)=0.02, P(B and C) = 0.06 P(A and…

Q: What is the probability that he must stop a. At both lights. b. At the first light but not at the…

A: Given : P (He must stop at the first light) = 0.35 P ( Stopping at the second light) = 0.65 P (…

Q: 1. In the communication system below the probability of transmitting ("B" before) symbols 1 and are:…

A: From the given information, P(B1)=0.7 P(B0)=0.3 P(A1|B1)=0.8 P(A0|B1)=0.2 P(A0|B0)=0.9 P(A1|B0)=0.1…

Q: ly please

Q: The sum of all probabilities must be equal to 1 2 3.14 10

A: Answer:- We know that the probability of an event lies between the range from 0 to 1. That is,…

Q: On a December day, the probability of snow is .30. The probability of a "cold" day is .50. The…

A: Given On a December day, the probability of snow is .30. The probability of a "cold" day is .50.…

Q: The probability that event M occurs is .68. The probability that event R occurs is .42. If p is the…

A: Given that Probability that event M occurs 0.68 Probability that event R occurs 0.42

Q: Find the probability of selecting 9 or more girls. 00.122 00.435 00.212 O 0.001

A: Given that The probabilities corresponding to the 14 possible values of x are summarized in the…

Q: U and V are mutually exclusive events. P(U) = 0.29; P(V) = 0.49. Find: a. P(U and V) = b. P(U|V)= c.…

A: The given probabilities are PU=0.29;PV=0.49. And also events U and V are mutually exclusive events.

Q: Find P(A or B or C) for the given probabilities. P(A)=0.39, P(B)=0.24, P(C)=0.18 P(A and…

Q: a. A₁ U A₂ b. An A [Hint: (A, U. A₁ U A₂ U A3 C.

A: P(A1)=0.22, P(A2)=0.25Note: According to bartelby question answer guidelines an expert can solve…

Q: 3. A Catholic couple has 5 children. Assuming that birth of a boy or a girl is equally likely,…

Q: Ans. 1/4 Q.22 Two fair coins are tossed. Let A denote the event "both faces are heads" and B denote…

A: The sample space for the tossing of coins is S=T,T,T.H,H,T,T,T A=H,HB=H,T,T,H A∩B=ϕ Thus A and B…

Q: Suppose that P(A)= 0.6 and P(B)= 0.5. If events A and B are independent, find the probabilities:…

Q: A family has 5 children, either boy or girl. The probability of each outcome is equal. Let A="the…

A: Given A="the first child is a girl"We can have first child to be girl in 1 way only.For each other…

Q: Mike took his final exam of information theory last week. According to his score, The probability of…

A: 1. He got full information about getting scholarship 2. For parsing, he can get A, B or C. Since…

Q: U and V are mutually exclusive events. P(U) = 0.28; P(V) = 0.59. Find: a. P(U and V) = b.…

A: Solution: Given Information; Let U and V are mutually exclusive events. P(U)= 0.28 P(V)=0.59

Q: Find P(A or B or C) for the given probabilities. P(A) = 0.33, P(B) = 0.24, P(C)= 0.19 P(A and B) =…

Q: The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given…

A: Given that P(A)=0.35, P(B) = 0.22, P(C)=0.18 P(A and B) 0.11, P(A and C)=0.03, P(B and C)=0.08 , P(A…

Q: U and V are mutually exclusive events. P(U) = 0.3; P(V) = 0.49. Find: a. P(U and V) = b. P(UIV) = c.…

Q: U and V are mutually exclusive events. P(U) = 0.16; P(V) = 0.59. Find: a. P(U and V) = b. P(U|V) =…

A: Two events U and V are given.

Q: The probability of two events A and B are 0.25 and 0.41 respectively. P(A and B) = 0.36 then find…

Q: Ans. 11/30 Q.20 A coin and a die are thrown together. Find the chance of throwing a head and 5 or a…

A: Probability is a branch of mathematics or statistics which is basically deals with the chances of…

Q: U and Vare mutually exclusive events. P(U) = 0.21; P(V) = 0.6. Find: a. P(U and V) = b. P(UIV) = c.…

A: According to the given information, We know that, U and V are mutually exclusive events. P(U)=0.21…

Concept explainers

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.

Topic Video

Question

2. The probabilities of events A and B are P(A) and P(B) respectively.
5
Р(4)
1
P(AN B)
=7
P(AU B) = q
12
Find, in terms of q,
а. Р(В),
b. P(A|B).
Given that A and B are independent events,
c. find the value of q.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Discrete Probability Distributions$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.

Similar questions

Let A and B be independent events. Express the probability P(A ∪ B) in terms of the probabilities of A and B.
Solve Q23
Please help how do I explain these probabilities using complete sentences
We are given that P(A | B) = 0.4 and P(A) = 0.3. Since P(A | B) ≠ P(A), the occurrence of event B changes the probability that event A will occur. This implies that A and B are ---Select--- not independent independent events.So, to determine P(A and B), we can apply the general multiplication rule for events. Recall that P(B) = 0.9. P(A and B) = P(B) · P(A | B)
Match the probabilities with the commands. In the answers, the first command stated is for EXCEL and the second is for the Tl calculator. 1. P(X = a) 2. P(X ≤ a) 3. P(X a) 5. P(X> a) 1. 2. 3. 4. [Choose ] [Choose ] =BINOM.DIST(r,n,p,TRUE) or binomcdf(n,p,r) =BINOM.DIST(r-1,n,p,TRUE) or binomcdf(n,p,r-1) -1- BINOM.DIST(r.n.p,TRUE) or 1 -binomcdf(n.p.r) 1- BINOM.DIST(r-1.n.p.TRUE) or 1 -binomcdf(n.p.r-1) -BINOM.DIST(r.n.p.FALSE) or binompdf(n.p.r)
Please answer Both (:
Use the Test for Independence to determine if events A and B are independent. P(A) = 0.7, P(B) = 0.8, P(An B) = 0.56 Select the correct choice below and fill in the answer box(es) to complete your choice. (Type an integer or a decimal.) O A. Events A and B are not independent because P(A U B)= | and P(A) + P(B) - P(An B)= O B. Events A and B are independent because P(An B) = 0.56 and P(A).P(B) = O C. Events A and B are independent because P(A U B)= and P(A) + P(B)- P(An B) = O D. Events A and B are not independent because P(An B) = 0.56 and P(A) P(B) =.
A and B are two events, P(A)= 0.21, P(B)=0.32, P(A|B)= 0.61 Find P(A and B)
Suppose we know that the probabilities P(A) = .5, P(B|A) = .3 and P(A or B) =.3. What is the value for P(A and B)? What is the value for P(B)?
The probability of an integrated circuit passing a quality test is F. In a batch of 10 integrated circuits find the probabilities thati. 2 will failii. 8 will passiii. at least 2 will failiv. fewer than 2 will fail.
Please help
Solve Q21