2. The motor exerts a force F on the 40-kg crate as shown in the graph. Determine the speed of the crate when t = 3 s and when t = 6 s. When t = 0, the crate is moving downward at 8 m/s. F (N) 450 150 t(s) 6.
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- BOX 1.25m 34 Assuming no friction and the box starts at rest, what will be the speed of the box at the end of the ramp? m/s Word Bank: 4.9 We need the mass to calculate the speed 1.25 20 3.7 4.5 42.52. Determine the velocity of the 60-lb block A if the two blocks are released from rest and the 40-lb block B moves 2 ft the incline. The coefficient of up kinetic friction between both blocks and the inclined planes is u, =0.10. %3D Use Constraint Equations (for pulley), Equation of Motion (Newton's second law), and the Principle of Work and Energy. NOT allowed to use Chegg or other such websites. NOT allowed to use Chegg or other such 30° 60° IA 1172 Physics
- 4. The power provided by a force can also be written as P = dW /dt = F · d7/dt = F .ö. A force F = (3i – 2j + 6k)N is applied to an object moving with a velocity i = (2î – 3k) m/s. a. What is the power provided by this force? Does the object speed up or slow down or neither, if this force is the only unbalanced force acting on the object? b. Consider a force that is always perpendicular to the velocity. Does the object speed up or slow down or neither, if this force is the only unbalanced force acting on the object?For exercise, an athlete lifts a barbell that weighs 400 N from the ground to a height of 2.20 m at a constant speed in a time of 1.60 s. For the second time, the athlete completes the same task in 1.50 s. Match the answers with questions. metabolic energy metabolic power A. decreases B. increases C. not enough information D. stays the sameA 1400 kg car delivers a constant 42 hp to the drive wheels. We assume the car is traveling on a level road and that all frictional forces may be ignored.A) What is the acceleration of this car when its speed is 10 m/s?B) If the speed of the car is doubled, does its acceleration increase, decrease, or stay the same? Explain
- 3. A 150. kg roller coaster is released from rest at the top of a 50.0 m hill. How fast will it be goingif the second hill is 10 m high?QUESTION 7 From the diagram below, what is the speed of the block when it reaches point A at the lowest point on the surface? 2.00-kg block with an initial velocity of 5.00 m/s down the track Frictionless track В 9.00 m 5.00 m A a. 11.2 m/s b. 9.70 m/s C. 14.2 m/s d. 15.7 m/s е. 12.7 m/s8. A 534 N boy drops from a diving platform 12 m above the water. Find the boy's speed 4m above the water's surface. Then find his speed just before hitting the water.
- On the roller-coaster shown, a car is moving 10 m/s toward the right at point 1. Assuming no friction, calculate the speed of the car at point 4. 3 40 m 26 m 15 m 29.37 m/s 22.71 m/s 20.89 m/s 26.17 m/s A. D. В. 25.07 m/s Е. С. 24.29 m/s F.1. A roller coaster, shown below (h1 m/s = 40.0 m, h₂ = 16.0 m, h3 m), is pulled up to point A where it and its screaming occupants are released from rest. Assuming no friction, calculate the speed at point D. cci16 ceil6 ccil6 ceil6 ccil6 ce clo cci16 cci16 33 16 cci16 ccil6 ccN 6 ceil6 ccilo = 26.0 Cecil6 ceil6 ccil6 ccio cil6 cci16. 6 ccil6 cci16 cci16 ceil6 cc²4. Here we prove a version of the work-kinetic energy theorem for an object moving in 1-D subject to a constant force. Consider a mass m, traveling initially at speed v, on which a constant net force F is applied in the same direction as its motion over a distance d. After the net force has acted over this distance, the speed of the object is v2. In terms of m, F, v1, v2, and d only, V, A) What is the acceleration of the mass? t=0 m F d t>0_m B) What is the time over which the mass travels the V, distance d? [Use one equation of constant acceleration to find this.] C) Use another equation of constant acceleration to relate m, F, v,, v2, and d. Show that the product W = Fd is equal to the change in the mass’s kinetic energy.