2. The mean height of 25 male students who showed above average participation inCollege athletics was 54.1 inches with a standard deviation of 3.2 inches while30 male students who showed no interest in such participation had mean heightof 57.4 inches and a standard deviation of 4.1 inches. Test the hypothesis thatmale students who participated in college athletics are taller than other malestudents at 0.05 level of significance.A. - 3.350, reject Ho.В. — 3.350, ассеpt Но.С. 1.319, ассept Hо.D. 1.319, reject Ho.

There are two independent samples which follows normal distribution. We have to test whether the…

Answered: 2. The mean height of 25 male students…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A researcher conducted a research at a local high school wherein she found out that, among the 150 random respondents, the average number of texts sent is 135 with a sample standard deviation of 30. The population mean is 140. Use 1% level of significance. Find the z-value. )
The average amount of rainfall in Puerto Rico last month was 3.5 inches, according to the National Meteorology Center. Suppose that a normal distribution can be used and that the standard deviation is 0.8 inches. a. What percentage of the time was last month's rainfall greater than 4 inches? (3 points)b. What percentage of the time was rainfall less than 3 inches? (3 points)c. A month is considered extremely humid if the rainfall is 10% higher for that month. How much rainfall must be in April to be considered an extremely humid month? (3 points)
From checking Facebook while walking to class to posting photos on Instagram while eating in the Russell House - social media plays a significant role in the daily lives of college students. The average amount of time a college student spends on social media in the morning (6:00 am - 11:59 am) is normally distributed with a mean of 48 minutes per day and a standard deviation of 12 minutes per day. Suppose on a given morning a college student spends 85 minutes on social-media. Is this unusual?. OA. Not enough information OB. Yes OC. No
There are 24 students enrolled in an introductory statistics class at a small university. As an in-class exercise the students were asked how many hours of television they watch each week. The nm = 13 male students watched an average of 6 hours of television per week with standard deviation 4.24 hours. The ng = 11 female students watched an average of 3.91 hours of television per week with a standard deviation of 3.48 hours. Assume that the students enrolled in the statistics class are representative of all students at the university. The standard error of the differences , and x, is about SE = 1.667. Use the normal distribution to test, at the 5% level, if male students at this university watch, on average, more television than female students. Include all details of the test. z = i p-value = i There is evidence that males at this university watch significantly more television, on average, than female students.
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1540 and a standard deviation of 299. The local college includes a minimum score of 2377 in its admission requirements. What percentage of students from this school earn scores that fail to satisfy the admission requirement? Give your answer as a percentage rounded to one decimal place.
Joan’s finishing time for the Bolder Boulder 10K race was 1.67 standard deviations faster than the women’s average for her age group. There were 415 women who ran in her age group. Assuming a normal distribution, how many women ran faster than Joan?
A researcher collected data from Boston police officers and found that on average they spent 14.3 hours on in-service training per year with a standard deviation of 3.2. The department offers bonuses for officers in the top 10 percent on in-service training completed. Would the officer who did 22 hours of training get the bonus?
The heights of adult men in America are normally distributed, with a mean of 69.3 inches and a standard deviation of 2.67 inches. The heights of adult women in America are also normally distributed, but with a mean of 64.8 inches and a standard deviation of 2.54 inches. a) If a man is 6 feet 5 inches tall, what is his z-score? z = 3.26
After the pandemic hit and people were forced to spend more time indoors, there have been a suspicion among health professionals. that people are eating more and thus gaining weight. In 2018, the average weight of 192 pounds, and health experts want to know if that average weight of the American male has gone up during this pandemic. d. A sample of 50 American males yeilded a sample average weight of 195 pounds and a sample standard deviation of 14.5 pounds. What is your conclusion at the 5% level of significance? (be sure to state your conclusion in the context of this problem) e. Would your conclusion change if the level of significance were changed to 1%? Briefly explain.
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 99.3-cm and a standard deviation of 1.5-cm. For shipment, 25 steel rods are bundled together.Find P27, which is the average length separating the smallest 27% bundles from the largest 73% bundles. P27 =
Assume that the heights of men are normally distributed with a mean of 68.1inches and a standard deviation of 2.8 inches. If 64 men are randomly selected, find theprobability that they have a mean height greater than 69.1 inches.
Cotinine levels were measured in a group of non-smokers exposed to tobacco smoke (n =40), the mean of the sample was 60.58 ng/Ml and the standard deviation was 138.08 ng/Ml. Also, cotinine levels were measured in a group of non-smokers not exposed to tobacco smoke(n =40), the mean of the sample was 16.35 ng/mL and the standard deviation was 62.53 ng/mL. Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced. Use a 0.05 significance level to test the claim that non-smokers exposed to tobacco smoke have a higher mean nicotine level than nonsmokers not exposed to tobacco smoke. a)Define the parameter and state null and alternative hypothesis b)Test Statistics c) Critical Value Approach d) Conclusion

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