2. The intracellular concentration of glucose-6-phosphate and fructose-6-phosphateare measured inside the cell of a patient and the following values were obtained:(glucose-6-phosphate] = 8 x 10-5 M[fructose-6-phosphate] = 1.5 x 10-5 M%3D%3DIs this reaction at equilibrium?What is the value of Q?.What do you predict the sign for AG will be?Calculate AG for this reaction.

Answered: 2. The intracellular concentration of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2. The intracellular concentration of glucose-6-phosphate and fructose-6-phosphate
are measured inside the cell of a patient and the following values were obtained:
(glucose-6-phosphate] = 8 x 10-5 M
[fructose-6-phosphate] = 1.5 x 10-5 M
%3D
%3D
Is this reaction at equilibrium?
What is the value of Q?.
What do you predict the sign for AG will be?
Calculate AG for this reaction.

Expert Solution

Step 1

If the value of $\begin{array}{rcl} ∆ G ° \end{array}$ is negative will represent the reaction conditions are favorable. If the value of $\begin{array}{rcl} ∆ G ° \end{array}$ is positive will represent the reaction conditions are unfavorable. When the reaction is an equilibrium value of $\begin{array}{rcl} ∆ G ° \end{array}$ is zero. Unit of $\begin{array}{rcl} ∆ G ° \end{array}$ is kJ per mol.

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