2. The Henry's Law constant for hydrogen sulphide (H,S) in water (H,O) at 25 °C is 5.5 x 10ʻ kPa. a. Calculate how much H,S is dissolved in water in mg H,S/ litre H;O if the partial pressure of H,S is 50 mmHg. 1 atm = 760 mmHg = 100 kPa. Atomic masses in g/mol: S: 32; H: 1; 0:16. b. Why is Henry's Law more suitable than Raoult's Law to calculate how much H;S is dissolved in water in this particular case?
2. The Henry's Law constant for hydrogen sulphide (H,S) in water (H,O) at 25 °C is 5.5 x 10ʻ kPa. a. Calculate how much H,S is dissolved in water in mg H,S/ litre H;O if the partial pressure of H,S is 50 mmHg. 1 atm = 760 mmHg = 100 kPa. Atomic masses in g/mol: S: 32; H: 1; 0:16. b. Why is Henry's Law more suitable than Raoult's Law to calculate how much H;S is dissolved in water in this particular case?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![2. The Henry's Law constant for hydrogen sulphide (H,S) in water (H,O) at 25 °C is 5.5 x 104 kPa.
a. Calculate how much H,S is dissolved in water in mg H;S/ litre H;O if the partial pressure
of H,S is 50 mmHg. 1 atm = 760 mmHg = 100 kPa. Atomic masses in g/mol: S: 32; H: 1;
0:16.
b. Why is Henry's Law more suitable than Raoult's Law to calculate how much H;S is
dissolved in water in this particular case?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F98a2975c-b075-4e7f-95a3-3742d529c071%2Fa4de1beb-ba38-43fa-8627-1c5fe4536be7%2F8t48pyv_processed.png&w=3840&q=75)
Transcribed Image Text:2. The Henry's Law constant for hydrogen sulphide (H,S) in water (H,O) at 25 °C is 5.5 x 104 kPa.
a. Calculate how much H,S is dissolved in water in mg H;S/ litre H;O if the partial pressure
of H,S is 50 mmHg. 1 atm = 760 mmHg = 100 kPa. Atomic masses in g/mol: S: 32; H: 1;
0:16.
b. Why is Henry's Law more suitable than Raoult's Law to calculate how much H;S is
dissolved in water in this particular case?
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