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2. The following circuit shows a discrete common emitter BJT amplifier. The BJT has B=100, Cx = 5 pF, Cu=1 pF and VA = 00, VT = 25 mV (1) Find DC collector current (Ic), transconductance (gm), Ix and re.

2. The following circuit shows a discrete common emitter BJT amplifier. The BJT has B=100, Cx = 5 pF, Cu=1 pF and VA = 00, VT = 25 mV (1) Find DC collector current (Ic), transconductance (gm), Ix and re.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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2. The following circuit shows a discrete common emitter BJT amplifier. The BJT has B-100, Cx = 5 pF, Cµ =1 pF and VA= 00, VT = 25 mV (1) Find DC collector current (Ic), transconductance (gm), In and re. (2) Draw small signal equivalent circuit of the amplifier in low frequency band, and determine low corner frequency(@L) using approximation method (using time constants). (3) Draw small signal equivalent circuit of the amplifier in high frequency band, and determine the high corner frequency( OH) using approximation method (using time constants). VcC 9V RC 20KQ CC2 O vout 1µF Rsig C1 RL 20ko 1µF 20kQ RB Vsig CE 1MQ 10µF 0.1mA
Transcribed Image Text:2. The following circuit shows a discrete common emitter BJT amplifier. The BJT has B-100, Cx = 5 pF, Cµ =1 pF and VA= 00, VT = 25 mV (1) Find DC collector current (Ic), transconductance (gm), In and re. (2) Draw small signal equivalent circuit of the amplifier in low frequency band, and determine low corner frequency(@L) using approximation method (using time constants). (3) Draw small signal equivalent circuit of the amplifier in high frequency band, and determine the high corner frequency( OH) using approximation method (using time constants). VcC 9V RC 20KQ CC2 O vout 1µF Rsig C1 RL 20ko 1µF 20kQ RB Vsig CE 1MQ 10µF 0.1mA
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