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2. State the domain and range of f(x) ==Vx +2 5 D:[-2,0) D:[-2.) В. D:(-0,00) C. D:[0,0) D. R:(-0,0) R:[2.) A. 3 R:[0,0) R: ,00 5

2. State the domain and range of f(x) ==Vx +2 5 D:[-2,0) D:[-2.) В. D:(-0,00) C. D:[0,0) D. R:(-0,0) R:[2.) A. 3 R:[0,0) R: ,00 5

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Question:** 2. State the domain and range of \( f(x) = \frac{3}{5} \sqrt[3]{x} + 2 \) **Options:** **A.** Domain (D): \([-2, \infty)\) Range (R): \(\left[\frac{3}{5}, \infty\right)\) **B.** Domain (D): \([-2, \infty)\) Range (R): \([0, \infty)\) **C.** Domain (D): \((-\infty, \infty)\) Range (R): \((-\infty, \infty)\) **D.** Domain (D): \([0, \infty)\) Range (R): \([2, \infty)\) **Explanation:** The function \( f(x) = \frac{3}{5} \sqrt[3]{x} + 2 \) involves a cube root function, which is defined for all real numbers. Therefore, the domain (D) is \((-\infty, \infty)\). Since the cube root function can take any real value, the range (R) is also \((-\infty, \infty)\).
Transcribed Image Text:**Question:** 2. State the domain and range of \( f(x) = \frac{3}{5} \sqrt[3]{x} + 2 \) **Options:** **A.** Domain (D): \([-2, \infty)\) Range (R): \(\left[\frac{3}{5}, \infty\right)\) **B.** Domain (D): \([-2, \infty)\) Range (R): \([0, \infty)\) **C.** Domain (D): \((-\infty, \infty)\) Range (R): \((-\infty, \infty)\) **D.** Domain (D): \([0, \infty)\) Range (R): \([2, \infty)\) **Explanation:** The function \( f(x) = \frac{3}{5} \sqrt[3]{x} + 2 \) involves a cube root function, which is defined for all real numbers. Therefore, the domain (D) is \((-\infty, \infty)\). Since the cube root function can take any real value, the range (R) is also \((-\infty, \infty)\).
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