Please explain 2. Sometimes, athletes illegally use anabolic steroids to increase muscle strength. A forensic chemist analyzessome tablets suspected of being a popular steroid. He determined that the substance in the tablets containsonly carbon, hydrogen, and oxygen in and has a molar mass of 300.14 g/mole. When a 1.200 g sample of thisstudy by combustion analysis, 3.516 g of CO2 and 1.007 g of H₂O are collected. What is the molecular formulafor the substance?MassMolar massCO₂H₂OCHOCO₂H₂Og1 mol CO₂44.01 g CO₂1 mol H₂O18.02g H₂O_gCHO–44.01g/mol18.02 g/mol12.01g/mol1.008 g/mol16.00 g/mol1 mol C1 mol CO₂2 mol H1 mol H₂OgH+molesmol CMol HMole ratiomol CMultiply untilwholeg012.01g C1 mol Cmol H 1.008g H1 mol H1 mol O16.00g OCFinalempiricalratiomol Og H

The empirical formula is the smallest ratio of integers which gives the correct ratio of elements…

2. Sometimes, athletes illegally use anabolic steroids to increase muscle strength. A forensic chemist analyzes some tablets suspected of being a popular steroid. He determined that the substance in the tablets contains only carbon, hydrogen, and oxygen in and has a molar mass of 300.14 g/mole. When a 1.200 g sample of this study by combustion analysis, 3.516 g of CO₂ and 1.007 g of H₂O are collected. What is the molecular formula for the substance? Mass Molar mass Mole ratio CO₂ H₂O C H O CO₂ H₂O g 1 mol CO₂ 44.01 g CO₂ 1 mol H₂O 18.02g H₂O CHO- 44.01g/mol 18.02 g/mol 12.01g/mol 1.008 g/mol 16.00 g/mol 1 mol C 1 mol CO₂ 2 mol H 1 mol H₂O moles mol C Mol H go mol C Multiply until whole 12.01g C 1 mol C mol H 1.008g H 1 mol H g01 mol O 16.00g O C Final empirical ratio mol O

2. Sometimes, athletes illegally use anabolic steroids to increase muscle strength. A forensic chemist analyzes some tablets suspected of being a popular steroid. He determined that the substance in the tablets contains only carbon, hydrogen, and oxygen in and has a molar mass of 300.14 g/mole. When a 1.200 g sample of this study by combustion analysis, 3.516 g of CO₂ and 1.007 g of H₂O are collected. What is the molecular formula for the substance? Mass Molar mass Mole ratio CO₂ H₂O C H O CO₂ H₂O g 1 mol CO₂ 44.01 g CO₂ 1 mol H₂O 18.02g H₂O CHO- 44.01g/mol 18.02 g/mol 12.01g/mol 1.008 g/mol 16.00 g/mol 1 mol C 1 mol CO₂ 2 mol H 1 mol H₂O moles mol C Mol H go mol C Multiply until whole 12.01g C 1 mol C mol H 1.008g H 1 mol H g01 mol O 16.00g O C Final empirical ratio mol O

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter3: Stoichiometry

Section: Chapter Questions

Problem 5RQ: Fig. 5-5 illustrates a schematic diagram of a combustion device used to analyze organic compounds....

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

Please explain

2. Sometimes, athletes illegally use anabolic steroids to increase muscle strength. A forensic chemist analyzes
some tablets suspected of being a popular steroid. He determined that the substance in the tablets contains
only carbon, hydrogen, and oxygen in and has a molar mass of 300.14 g/mole. When a 1.200 g sample of this
study by combustion analysis, 3.516 g of CO2 and 1.007 g of H₂O are collected. What is the molecular formula
for the substance?
Mass
Molar mass
CO₂
H₂O
C
H
O
CO₂
H₂O
g
1 mol CO₂
44.01 g CO₂
1 mol H₂O
18.02g H₂O
_gCHO–
44.01g/mol
18.02 g/mol
12.01g/mol
1.008 g/mol
16.00 g/mol
1 mol C
1 mol CO₂
2 mol H
1 mol H₂O
gH+
moles
mol C
Mol H
Mole ratio
mol C
Multiply until
whole
g0
12.01g C
1 mol C
mol H 1.008g H
1 mol H
1 mol O
16.00g O
C
Final
empirical
ratio
mol O
g H

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