1. Calculate for the frequency of a 260 nm light and 627 nm light. What can you say about their values? Discuss and compare. (10 pts). 2. Calculate for the energy of a 420 nm light. (5pts) 2. Solve for the equilibrium constant and the free energy change of the following reactions (10 pts) Sn+2 Cu²* = Sn²+ + 2 Cu* a. 3. Fe2+2 Ag C. Zn+Cu²+ Fe + 2 Ag* Zn²+ + Cu d. Au|Au(NO3)3||Ca(NO3)2 Ca e. Sn2+, Sn4||Hg2+, Hg2+ Calculate the Ecell of the reaction Co(s) + Fe2+(aq) → Co2+(aq) + Fe(s) given that [Co2+] = 0.25 M and [Fe2+] = 0.94 M. (5pts)

Understanding Business
12th Edition
ISBN:9781259929434
Author:William Nickels
Publisher:William Nickels
Chapter1: Taking Risks And Making Profits Within The Dynamic Business Environment
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1. Calculate for the frequency of a 260 nm light and 627 nm light. What can you say about their values?
Discuss and compare. (10 pts).
2. Calculate for the energy of a 420 nm light. (5pts)
Transcribed Image Text:1. Calculate for the frequency of a 260 nm light and 627 nm light. What can you say about their values? Discuss and compare. (10 pts). 2. Calculate for the energy of a 420 nm light. (5pts)
2.
Solve for the equilibrium constant and the free energy change of the following reactions (10 pts)
Sn+2 Cu²* = Sn²+ + 2 Cu*
a.
3.
Fe2+2 Ag
C.
Zn+Cu²+
Fe + 2 Ag*
Zn²+ + Cu
d. Au|Au(NO3)3||Ca(NO3)2 Ca
e. Sn2+, Sn4||Hg2+, Hg2+
Calculate the Ecell of the reaction Co(s) + Fe2+(aq) → Co2+(aq) + Fe(s) given that [Co2+] =
0.25 M and [Fe2+] = 0.94 M. (5pts)
Transcribed Image Text:2. Solve for the equilibrium constant and the free energy change of the following reactions (10 pts) Sn+2 Cu²* = Sn²+ + 2 Cu* a. 3. Fe2+2 Ag C. Zn+Cu²+ Fe + 2 Ag* Zn²+ + Cu d. Au|Au(NO3)3||Ca(NO3)2 Ca e. Sn2+, Sn4||Hg2+, Hg2+ Calculate the Ecell of the reaction Co(s) + Fe2+(aq) → Co2+(aq) + Fe(s) given that [Co2+] = 0.25 M and [Fe2+] = 0.94 M. (5pts)
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