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2. Shown in the graph below is the 14- 13 titration curve that results when 12 11 25.0mL 0.200M HCIO is titrated with 0.200M NAOH. 10 9. 8- a. Label the following points on the curve: i. equivalence point half equivalence point buffer region 5- ii. ii. b. Draw a second curve on the 0+ 5 20 10 25 graph that would result from the titration of 25.0mL of 15 30 35 40 45 Volume of 0.200 M NaOH Added (mL) 0.200M HCIO, with 0.200M NaOH. c. A student proposes creating a buffer by dissolving 0.010 mol of NaCIO,(s) in 100.mL of 0.100M HCIO,. Explain why the resulting solution would not be a buffer. 654 321

2. Shown in the graph below is the 14- 13 titration curve that results when 12 11 25.0mL 0.200M HCIO is titrated with 0.200M NAOH. 10 9. 8- a. Label the following points on the curve: i. equivalence point half equivalence point buffer region 5- ii. ii. b. Draw a second curve on the 0+ 5 20 10 25 graph that would result from the titration of 25.0mL of 15 30 35 40 45 Volume of 0.200 M NaOH Added (mL) 0.200M HCIO, with 0.200M NaOH. c. A student proposes creating a buffer by dissolving 0.010 mol of NaCIO,(s) in 100.mL of 0.100M HCIO,. Explain why the resulting solution would not be a buffer. 654 321

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2. Shown in the graph below is the 14- 13 12 11 10 9. 8- titration curve that results when 25.0mL 0.200M HCIO is titrated with 0.200M NAOH. a. Label the following points on the curve: equivalence point ii. half equivalence point buffer region i. 5. ii. 2. b. Draw a second curve on the 0- 10 15 20 25 graph that would result from the titration of 25.0mL of 5 30 35 40 45 Volume of 0.200 M NaOH Added (mL) 0.200M HCIO, with 0.200M NaOH. c. A student proposes creating a buffer by dissolving 0.010 mol of NaCIO,(s) in 100.mL of 0.100M HCIO,. Explain why the resulting solution would not be a buffer. 654 321 Hd
Transcribed Image Text:2. Shown in the graph below is the 14- 13 12 11 10 9. 8- titration curve that results when 25.0mL 0.200M HCIO is titrated with 0.200M NAOH. a. Label the following points on the curve: equivalence point ii. half equivalence point buffer region i. 5. ii. 2. b. Draw a second curve on the 0- 10 15 20 25 graph that would result from the titration of 25.0mL of 5 30 35 40 45 Volume of 0.200 M NaOH Added (mL) 0.200M HCIO, with 0.200M NaOH. c. A student proposes creating a buffer by dissolving 0.010 mol of NaCIO,(s) in 100.mL of 0.100M HCIO,. Explain why the resulting solution would not be a buffer. 654 321 Hd
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