2. Projectiles 1 and 2 are launched over level ground with the same speed but at different angles. Which hits the ground first? Ignore air resistance. A. Projectile 1 hits first. B. Projectile 2 hits first. C. They hit at the same time. D. There's not enough information to tell. 2.
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- A home run is hit in such a way that the baseball just clears a wall 21.0 m high, located 130 m from home plate. The ball is hit at an angle of 35.0 to the horizontal, and air resistance is negligible. Find (a) the initial speed of the ball, (b) the time it takes the ball to reach the wall, and (c) the velocity components and the speed of the ball when it reaches the wall. (Assume the ball is hit at a height of 1.00 m above the ground.)A student throws a 2.5kg ball horizontally off the top of a building with an initial speed of 4.25 m/s. At the same time, another student throws a 1.12kg ball along the same trajectory with the same initial speed. Which of the balls hits the ground first? a. The 2.5kg ball. b. They hit at the same time. c. The 1.12kgball.A cannon ball is fired horizontally from a height of 20 m and strikes the ground at an angle of 45°. At what speed was the cannon ball fired? A. 14 m/s. B. 20 m/s. C. 28 m/s. D. 32 m/s. E. 40 m/s.
- 10. A military jet flies horizontally with a velocity of 450 m/s and 20,000 m above the ground. When the jet is straight above an artillery gun a shell is fired. Assuming the shell hits the jet. a. Calculate the horizontal component of the initial velocity of the shell. b. Calculate the vertical component of the initial velocity of the shell.5. A bullet is fired at an initial velocity of 150 m/s and an angle of 56° at the top of a 120 m tall building. Neglecting air resistance, determine the following: a. The maximum height above the level ground that can be reached by the bullet. b. The time for the bullet to hit the ground. c. The velocity with which the bullet will hit the ground.9. A ball is rolled on the top of a table which is 1.5 meters high from the ground at a rate of 2 m/s. What is the horizontal velocity of the projectile? A. O m/s C. 1.5 m/s B. 1 m/s D. 2 m/s
- A soccer ball leaves the ground at an angle of 48° at an initial speed of 15.0m/s. Calculate: a. The time the ball is in the air. b. The horizontal displacement of a ball. c. The highest point on its trajectory.1. In a practice session, Iris hits a ball horizontally with a speed of 36 m/s from a height of 3.1 m. The ball travels until it hits the ground. a. Determine the time the ball is in the air. b. Determine the horizontal distance traveled by the ball. c. Calculate the ball’s velocity as it hits the ground.3. A projectile is launched at an elevated target with an initial velocity of of vo = 200 m/s in a direction making an angle of 30 degrees from the horizontal. Vo=200 m/s 500 m 30 R a. Determine the time of flight from A to B. b. Determine the range R. c. Determine the impact velocity at the target.
- A golf ball is driven off a tree that is elevated 10m above fairway. The initial velocity of the ball is 40m/s with an angle of 40° at the horizontal. a. Maximum height? b. Range? c. Velocity of ball when it reaches fairway?9. A ball was kicked from the ground at a velocity of 22m/s in a direction making an angle of 25 degrees upward with the horizontal. What is the maximum height reached by the object? a. b. How long was the ball in air? c. What is the horizontal range of the object? d. What is the magnitude (angle) of the velocity of the ball when it hits the ground?6. man stands on the roof of a 50 m tall building and throws a ball with a speed of 25 m/s at 40° above the horizontal. If we ignore the air resistance; a. Find the vertical and horizontal components of the ball's initial velocity. b. Find the maximum height above the ground that the ball reaches. c. Find the ball velocity (in unit vector nutation) just before it strikes the ground. d. At what horizontal distance from the edge of the building does the ball strikes the ground? e. What is the vertical acceleration of the ball at the maximum height? a. Vox 19.15 m/s Voy 16.07 m/s b. y = 50+ 13.18 = 63.18 m e. c. Vx = Vox = 19.15 m/s v=vxî + vyĵ = 19.15î — 35.18ĵ d. x = 100.16 m ay = -9.8 m/s² Vy = -35.18 m S 0000000000 00 DO 00 00 vo 40° 50 m