2. Now add all single-digit numbers from Step 1.4 + 4 + 8 + 2 + 3 + 1 + 7 + 8 = 373. Add all digits in the odd places from right to left in the card number.6 + 6 + 0 + 8 + 0 + 7 + 8 + 3 = 384. Sum the results from Step 2 and Step 3.37 + 38 = 755. If the result from Step 4 is divisible by 10, the card number is valid; otherwise,it is invalid. For example, the number 4388576018402626 is invalid, but thenumber 4388576018410707 is valid.Write a program that prompts the user to enter a credit card number as a longinteger. Display whether the number is valid or invalid. Design your program touse the following methods:/** Return true if the card number is valid */public static boolean isValid(long number)/** Get the result from Step 2 */public static int sumofDoubleEvenPlace(long number)/** Return this number if it is a single digit, otherwise,* return the sum of the two digits */public static int getDigit(int number)/** Return sum of odd-place digits in number */public static int sumof0ddPlace(long number)/** Return true if the digit d is a prefix for number */public static boolean prefixMatched(long number, int d)/** Return the number of digits in d */public static int getSize(long d)/** Return the first k number of digits from number. If the* number of digits in number is less than k, return number. */public static long getPrefix(long number, int k)Here are sample runs of the program: (You may also implement this program byreading the input as a string and processing the string to validate the credit card.) (Financial: credit card number validation) Credit card numbers follow certain pat-terns. A credit card number must have between 13 and 16 digits. It must start with:4 for Visa cards5 for Master cards37 for American Express cards6 for Discover cardsIn 1954, Hans Luhn of IBM proposed an algorithm for validating credit cardnumbers. The algorithm is useful to determine whether a card number is enteredcorrectly or whether a credit card is scanned correctly by a scanner. Credit cardnumbers are generated following this validity check, commonly known as theLuhn check or the Mod 10 check, which can be described as follows (for illustra-tion, consider the card number 4388576018402626):1. Double every second digit from right to left. If doubling of a digit results in atwo-digit number, add up the two digits to get a single-digit number.4388576018402626→ 2 * 2 = 4→ 2 * 2 = 4→ 4 * 2 = 8→ 1 * 2 = 26 * 2 = 12 (1+ 2 = 3)→ 5 * 2 = 10 (1+ 0 = 1)→ 8 * 2 = 16 (1 + 6 = 7)→ 4 * 2 = 8

2. Now add all single-digit numbers from Step 1. 4 + 4 + 8 + 2 + 3 + 1 + 7 + 8 = 37 3. Add all digits in the odd places from right to left in the card number. 6 + 6 + 0 + 8 + 0 + 7 + 8 + 3 = 38 4. Sum the results from Step 2 and Step 3. 37 + 38 = 75 5. If the result from Step 4 is divisible by 10, the card number is valid; otherwise, it is invalid. For example, the number 4388576018402626 is invalid, but the number 4388576018410707 is valid.

2. Now add all single-digit numbers from Step 1. 4 + 4 + 8 + 2 + 3 + 1 + 7 + 8 = 37 3. Add all digits in the odd places from right to left in the card number. 6 + 6 + 0 + 8 + 0 + 7 + 8 + 3 = 38 4. Sum the results from Step 2 and Step 3. 37 + 38 = 75 5. If the result from Step 4 is divisible by 10, the card number is valid; otherwise, it is invalid. For example, the number 4388576018402626 is invalid, but the number 4388576018410707 is valid.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

2. Now add all single-digit numbers from Step 1.
4 + 4 + 8 + 2 + 3 + 1 + 7 + 8 = 37
3. Add all digits in the odd places from right to left in the card number.
6 + 6 + 0 + 8 + 0 + 7 + 8 + 3 = 38
4. Sum the results from Step 2 and Step 3.
37 + 38 = 75
5. If the result from Step 4 is divisible by 10, the card number is valid; otherwise,
it is invalid. For example, the number 4388576018402626 is invalid, but the
number 4388576018410707 is valid.
Write a program that prompts the user to enter a credit card number as a long
integer. Display whether the number is valid or invalid. Design your program to
use the following methods:
/** Return true if the card number is valid */
public static boolean isValid(long number)
/** Get the result from Step 2 */
public static int sumofDoubleEvenPlace(long number)
/** Return this number if it is a single digit, otherwise,
* return the sum of the two digits */
public static int getDigit(int number)
/** Return sum of odd-place digits in number */
public static int sumof0ddPlace(long number)
/** Return true if the digit d is a prefix for number */
public static boolean prefixMatched(long number, int d)
/** Return the number of digits in d */
public static int getSize(long d)
/** Return the first k number of digits from number. If the
* number of digits in number is less than k, return number. */
public static long getPrefix(long number, int k)
Here are sample runs of the program: (You may also implement this program by
reading the input as a string and processing the string to validate the credit card.)

(Financial: credit card number validation) Credit card numbers follow certain pat-
terns. A credit card number must have between 13 and 16 digits. It must start with:
4 for Visa cards
5 for Master cards
37 for American Express cards
6 for Discover cards
In 1954, Hans Luhn of IBM proposed an algorithm for validating credit card
numbers. The algorithm is useful to determine whether a card number is entered
correctly or whether a credit card is scanned correctly by a scanner. Credit card
numbers are generated following this validity check, commonly known as the
Luhn check or the Mod 10 check, which can be described as follows (for illustra-
tion, consider the card number 4388576018402626):
1. Double every second digit from right to left. If doubling of a digit results in a
two-digit number, add up the two digits to get a single-digit number.
4388576018402626
→ 2 * 2 = 4
→ 2 * 2 = 4
→ 4 * 2 = 8
→ 1 * 2 = 2
6 * 2 = 12 (1+ 2 = 3)
→ 5 * 2 = 10 (1+ 0 = 1)
→ 8 * 2 = 16 (1 + 6 = 7)
→ 4 * 2 = 8

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