Lets play a magic game. Pick any 4 digits integer, for example n = 1965. Perform following operations. Sort the digits in the number in descending order you will get m = 9651. Sort the digits in the number in ascending order you will get k= 1569. Let n = m-k = 9651-1569=8082. After repeating above three steps certain times, you will find n = 6174, and it will stay 6174 for ever! In other words if you start above three steps with initial n = 6174, you will find n is still 6174 at step 3! We call it number black hole. Write a C++ program to demonstrate this. Your program should let user to be able to test it as many times as the user wants as long as the user enters a 4-digits positive integer and your program should quits if the user enters anything else.
Lets play a magic game. Pick any 4 digits integer, for example n = 1965. Perform following operations. Sort the digits in the number in descending order you will get m = 9651. Sort the digits in the number in ascending order you will get k= 1569. Let n = m-k = 9651-1569=8082. After repeating above three steps certain times, you will find n = 6174, and it will stay 6174 for ever! In other words if you start above three steps with initial n = 6174, you will find n is still 6174 at step 3! We call it number black hole. Write a C++ program to demonstrate this. Your program should let user to be able to test it as many times as the user wants as long as the user enters a 4-digits positive integer and your program should quits if the user enters anything else.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Transcribed Image Text:Lets play a magic game.
Pick any 4 digits integer, for example n = 1965. Perform following operations.
Sort the digits in the number in descending order you will get m = 9651.
• Sort the digits in the number in ascending order you will get k = 1569.
• Let n = m-k = 9651-1569=8082.
After repeating above three steps certain times, you will find n = 6174, and it will stay
6174 for ever! In other words if you start above three steps with initial n = 6174, you will
find n is still 6174 at step 3! We call it number black hole.
Write a C++ program to demonstrate this. Your program should let user to be able to
test it as many times as the user wants as long as the user enters a 4-digits positive
integer and your program should quits if the user enters anything else.
Sample Design:
I/Lab2.cpp
// add statement to include iostream
// add statement to use namespace std
// declare all functions except main function here
int getNumberOfDigits (int n); //returns how many digits in positive number n
int* int2DynamicArray (int n, int numDigits); //convert n to an dynamic array
int dynamicArray2int (int* intPointer, int numDigits);
int sortDescending (int* intPointer, int numDigits) ;
sortAscending (int* intPointer, int numDigits);
getMegicHole (int n);
int
int
int main () {
int n = 1234, m, k, magicHole;
int pi
Cout << "Lab2:
Team number#
your real names " << endl;
while (1) {
//give input hints and get inputn from user
//quit if it is not a 4 digits integer
//
magicHole = getMegicHole (n);
//loop if it is not n.
return 0;
#Implement all functions you have declared here.
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