2. Lloyd rolls a 7.0 kg bowling ball down the alley for the league championship. One pin is still standing, and Lloyd hits it head-on with a velocity of 9.0 m/s. The 2.0 kg pin acquires a forward velocity of 14.0 m/s. What is the new velocity of the bowling ball? m=7.0kJ my + m,V2 = (m+m2)(Vf) %3D (7.0 V = 4.0mis V2=14.0mIS

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Chapter9: Linear Momentum And Collisions
Section: Chapter Questions
Problem 9.60P: A model rocket engine has an average thrust of 5.26 N. It has an initial mass of 25.5 g, which...
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2. Lloyd rolls a 7.0 kg bowling ball down the alley for the league championship. One pin is still
standing, and Lloyd hits it head-on with a velocity of 9.0 m/s. The 2.0 kg pin acquires a
forward velocity of 14.0 m/s. What is the new velocity of the bowling ball?
my + m,V2 = (m+m2)(Vf)
m=7.0Kg
m=20ky
V = 4.0 mIs
V2=14.0mIS
%3D
(7.0
Transcribed Image Text:2. Lloyd rolls a 7.0 kg bowling ball down the alley for the league championship. One pin is still standing, and Lloyd hits it head-on with a velocity of 9.0 m/s. The 2.0 kg pin acquires a forward velocity of 14.0 m/s. What is the new velocity of the bowling ball? my + m,V2 = (m+m2)(Vf) m=7.0Kg m=20ky V = 4.0 mIs V2=14.0mIS %3D (7.0
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