2. LeBron, a 250 lb basketball player, lands on his feet after completing a slam dunk and then immediately jumps up again to celebrate his basket. When his feet first touch the floor after the dunk is velocity is 5 m/s downward. When his feet leave the floor 0.5 s later, as he jumps back up, his velocity is 4 m/s upward. a. What is the impulse exerted on LeBron during this 0.5 s? b. What is the average net force exerted on LeBron during this 0.5 s?
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- A 0.13 kg baseball has a momentum of p = 11 kg*m/s as it is pitched toward home plate. A 4.2 kg bat swings at the baseball with a momentum of 28 kg*m/s and is in contact with the ball for 0.06 s. Assume the batter doesn't follow through like they should but instead the bat is at rest immediately after being in contact with the baseball (like bunting it). a.What is the magnitude of the velocity of the baseball just before coming in contact with the bat? b.What is the magnitude of the velocity of the baseball immediately after being struck by the bat? c.What is the magnitude of the impulse on the ball?ent G An impulse of 12.2 kg*m/s is deli x 361242/take 10 p Question 1 A warehouse employee is pushing a 30.0 kg desk across a floor at a constant speed of 0.50 m/s. What is the magnitude of the momentum of the desk? O 0.017 kg*m/s O 15.0 kg*m/s O 60 kg*m/s O 30.5 kg*m/s Question 2 10 pts Norton Antivirus: 19.99/YE Your special price is valid to Google Chrome istudy-helper.co The momentum of a 12kg dog racing to greet its owner has a Norton What is the dog's speed? Install O a CopA 0.13 kg baseball has a momentum of p = 11 kg*m/s as it is pitched toward home plate. A 4.2 kg bat swings at the baseball with a momentum of 28 kg*m/s and is in contact with the ball for 0.06 s. Assume the batter doesn't follow through like they should but instead the bat is at rest immediately after being in contact with the baseball (like bunting it). a.How much force was on the baseball when the bat was striking it? b.How much work was done on the baseball by the bat?
- 1. a. Starting from Newton's second law of motion, prove that impulse is equal to a change in momentum. b. A particle of mass m moves with a momentum of magnitude p. Show that the kinetic energy of the particle KE = i. =p²/2mA 100g ball traveling horizantally at 25 m/s strikes a wall and rebounds at 19 m/s. What is the magnitude of the impulse experienced by the ball during the rebound? A. 1.2 Ns B. 1.8 Ns C. 4.4 Ns D. 5.4 Ns E. 7.2 NsE6.) A ball experiences a change in momentum of 24 kg-m/s.a. What is the impulse acting on the ball?b. If the time of interaction is 0.15 s, what is the magnitude of the average force acting on the ball? Answer with the correct formula.
- You drop a steel ball and a clay ball, both of the same mass, from the same distance. The steel ball strikes the ground and rebounds with almost the same speed. The clay ball strikes the ground and sticks. Assume the collisions occur over roughly the same amount of time. Which ball exerted a greater force on the ground? Select the correct answer with the best explanation. A. The two exert the same force. Since they collide with the same initial momentum, they will exert thesame force.B. The clay ball exerts the greater force. Since it starts with some momentum and ends with no momen- tum, it undergoes a greater change in momentum than the steel ball, which rebounds with the same momentum (no change).C. The clay ball exerts the greater force. All of its energy is transferred to the floor, whereas the steelball rebounds with the same kinetic energy, doing no work on the floor.D. The steel ball exerts the greater force. Since it starts with some momentum and it reverses the direction of…Suppose F₁ = 2000 N. (Figure 1) You may want to review (Pages 262-266). Figure F, (N) F 0- 0 N. 2 4 6 1 of 1 -t (ms) Part A What impulse does the force shown in the figure exert on a 250 g particle? Express your answer in newton-seconds to two significant figures. WD ΑΣΦ J = Submit Previous Answers Request Answer X Incorrect; Try Again Provide Feedback ? N.SA golf ball m = 0.155 kg strikes a vertical concrete wall elastically with a horizontal velocity of v = 15 m/s. a. Write an expression for the magnitude of the impulse I experienced by the ball. b. If the ball was in contact with the wall for t = .1s, what is the magnitude of the force F the ball experienced in N? c. If the ball rebounds with only half the velocity it comes in with, what is the magnitude of the impulse in kg m/s? d. Determine the magnitude of the change in kinetic energy in the above situation. Give your answer in joules.
- I. Conceptual Physics. Justify your answer. 1. A 10-gram rubber ball and a 10-gram clay ball are thrown at a wall with equal initial speeds. The rubber ball bounces, the clay ball sticks. Which ball exerts a larger impulse on the wall? Justify your answer.B6Car 1 is traveling in the +x-direction at 10.0 m/s and Car 2 is stationary. Car 1 collides with, and sticks to, Car 2. Car 1 and Car 2 have masses of 995 kg and 1850 kg, respectively. You may ignore friction and other forces external to the system. a. Using the principle of conservation of momentum, find the velocity (magnitude and direction) of the combined system immediately after this perfectly inelastic collision. b. Find the fractional change in kinetic energy for this collision. In other words, determine