2. Lead ions react with chloride ions to create a precipitate as represented by the reaction below: Pb^ 2+ (aq) + 2Cl - (aq) -->PbCl 2 (s) A. How many grams of lead(II) chloride would be made if 16 grams of Cl- ions react with excess lead ion? B. How many moles of chloride ion would be needed to react with 0.068 moles of lead ion? C. How many grams of lead ion would be needed to produce 340 grams of lead(II) chloride precipitate?
2. Lead ions react with chloride ions to create a precipitate as represented by the reaction below: Pb^ 2+ (aq) + 2Cl - (aq) -->PbCl 2 (s) A. How many grams of lead(II) chloride would be made if 16 grams of Cl- ions react with excess lead ion? B. How many moles of chloride ion would be needed to react with 0.068 moles of lead ion? C. How many grams of lead ion would be needed to produce 340 grams of lead(II) chloride precipitate?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2. Lead ions react with chloride ions to create a precipitate as represented by the reaction below: Pb^ 2+ (aq) + 2Cl - (aq) -->PbCl 2 (s) A. How many grams of lead(II) chloride would be made if 16 grams of Cl- ions react with excess lead ion?
B. How many moles of chloride ion would be needed to react with 0.068 moles of lead ion?
C. How many grams of lead ion would be needed to produce 340 grams of lead(II) chloride precipitate?
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