2. Knight P7.37 The coefficient of kinetic friction between the 2.00 kg block in the figure below and the table is 0.300. What is the acceleration of the 2.00 kg block? Draw a free body diagram as part of your solution. 1.0 kg 2.0 kg Answers to one significant figure 1. 100 kg 2. 2 m/s² 3.0 kg
2. Knight P7.37 The coefficient of kinetic friction between the 2.00 kg block in the figure below and the table is 0.300. What is the acceleration of the 2.00 kg block? Draw a free body diagram as part of your solution. 1.0 kg 2.0 kg Answers to one significant figure 1. 100 kg 2. 2 m/s² 3.0 kg
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter4: Forces In One Dimension
Section: Chapter Questions
Problem 77A
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
Transcribed Image Text:2. Knight P7.37 The coefficient of kinetic friction
between the 2.00 kg block in the figure below and
the table is 0.300. What is the acceleration of the
2.00 kg block?
Draw a free body diagram as part of your solution.
1.0 kg
2.0 kg
Answers to one significant figure
1. 100 kg
2. 2 m/s²
3.0 kg

Transcribed Image Text:Useful information
Newton's 2nd law component form
ΣFx
= max
ΣFy = may
Static, kinetic, and rolling friction
Atwood's machine
F. < μg Fw
Fk=kFN
Fr=r FN
a (M + m)
-
g=a
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