2. In the previous example, you added 4 Boron-11 isotopes to 1 Boron-10 to make the average atomic mass 10.81. What ratio and relative percent of the isotopes were Boron-11 in the mixture? Hint: The total number of isotopes used was 5. The ratio is Boron-11 divided by Total Isotopes = .8 = 80% = .5 = 50% = .25 = 25% = 0.20 = 20%

2. In the previous example, you added 4 Boron-11 isotopes to 1 Boron-10 to make the average atomic mass 10.81. What ratio and relative percent of the isotopes were Boron-11 in the mixture? Hint: The total number of isotopes used was 5. The ratio is Boron-11 divided by Total Isotopes = .8 = 80% = .5 = 50% = .25 = 25% = 0.20 = 20%

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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