2. In the emitter follower discussed in the lectures, the output (emitter) voltage is 0.7V below the input (base) voltage. One way to remove this offset is to use a diode as shown below left. Suppose our input Vi=2V. Assume beta = 100, VCE,Sat=0V, VBE,ON=0.7, and diode V;=0.7. +5V +5V 1000 R1 1N4148 500 100 Scattering Limit oVo 10 V; o R=10 R2 1K T, = 25 °C 0.1 0.4 0.8 1.2 1.6 2.0 V, - Forward Voltage (V) 94 9170 a. Determine VB and Vo b. Verify your assumed state of the BJT from (a) c. Verify your assumed state of the diode from (a) 1,- Forward Current (mA)

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2. In the emitter follower discussed in the lectures, the output (emitter) voltage is 0.7V
below the input (base) voltage. One way to remove this offset is to use a diode as
shown below left. Suppose our input Vi=2V. Assume beta = 100, VCE,SAT=0V,
VBE,ON=0.7, and diode VF=0.7.
+5V
+5V
1000
R,
500
1N4148
100
Scattering Limit
oVo
10
V; o
RL=10
R2
т - 25°C
0.1
1K
0.4
0.8
1.2
1.6
2.0
V- - Forward Voltage (V)
94 9170
a.
Determine VB and Vo
b. Verify your assumed state of the BJT from (a)
C. Verify your assumed state of the diode from (a)
- Forward Current (mA)
Transcribed Image Text:2. In the emitter follower discussed in the lectures, the output (emitter) voltage is 0.7V below the input (base) voltage. One way to remove this offset is to use a diode as shown below left. Suppose our input Vi=2V. Assume beta = 100, VCE,SAT=0V, VBE,ON=0.7, and diode VF=0.7. +5V +5V 1000 R, 500 1N4148 100 Scattering Limit oVo 10 V; o RL=10 R2 т - 25°C 0.1 1K 0.4 0.8 1.2 1.6 2.0 V- - Forward Voltage (V) 94 9170 a. Determine VB and Vo b. Verify your assumed state of the BJT from (a) C. Verify your assumed state of the diode from (a) - Forward Current (mA)
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