2.In each of the cases below, determine if the given functioncould be a probability generating function for a discrete random variable X.If the asnwer is "no", provide a an detailed explanation why, and if the asnweris "yes", justify it, and determine P[X = 3] and P[X = k].a. G(s) = el-sb. G(s) = es-1c. G(s) = 232-$3

Step 1: Definition of a Probability Generating Function (pgf)A probability generating function (pgf)…

Answered: 2. In each of the cases below,…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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I need help with question #2 please Homework review
Solve the below problem. Table 1 contains the probabilities associated with each possible pair of values for Y, and Y, and is known as the joint probability function for Y,and Y2 Table: Probability function for Y, and Y, Yı_ y2 0 1 2 0 1/9 2/9 1/9 2/9 2/9 0 1 | 2 1/9 0 Find F (1, –2) and F(3,3).
Chapters: Normal and Exponential random variables. Q: There exist naturally occurring random variables that are neither discrete nor continuous. Suppose a group of people is waiting for one more person to arrive before starting a meeting. Suppose that the arrival time of the person is exponential with mean 4 minutes, and that the meeting will start either when the person arrives or after 5 minutes, whichever comes first. Let X denote the length of time the group waits before starting the meeting. - a. Find P(0
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is tth, then N (tth)=2. Suppose that the random variable X is defined in terms of N as follows: X=N²-2N-2. The values of X are given in the table below. Outcome ttt htt hhh tht tth hth hht thh Value of X 1 -2 -2 -2 -2 -3 -3 -3 Calculate the probabilities P (X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value X of X P(X=x) 0 0 0 0 0 00 X Ś
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Q P.6: On its way, a car meets 4 traffic lights, and the probability that each of them will be red is 0.5. Let X be a discrete random variable equal to the number of traffic lights that were green when the car arrived. X may take the values of 0, 1, 2, 3, 4. (Assume traffic lights are independent.) What is the probability distribution of X? The probability distribution of X is 3 4 p(x) 0.5 0.25 0.125 0.0625 0.0625 The probability of distribution of X is 3 p(x) 0.5 0.5 0.25 0.125 The probability of distribution of X is 3 4 p(x) 0.5 0.25 0.5 0.25 0.125 The probability distribution of X is 1 3 4 p(x) | 0.5 || 0.5 || 0.5 | 0.5 || 0.5 The probability of distribution of X is 3 4 p(x) || 0.0625 0.0625 0.125 0.25 0.5
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Suppose a and b be two possible values of a random variable X with a > b. The probability that X lies between a and b is P(a > X > b) = F (a) - F (b) Select one: O True O False
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Assume that 12 jurors are randomly selected from a population in which 83% of the people are Asian-Americans. Refer to the probability distribution table below and find the indicated probabilities. xx P(x)P(x) 0 0+ 1 0+ 2 0+ 3 0+ 4 0.0002 5 0.0013 6 0.0073 7 0.0305 8 0.0931 9 0.2021 10 0.296 11 0.2627 12 0.1069 Find the probability of exactly 7 Asian-Americans among 12 jurors.P(x=7)=P(x=7)= Find the probability of 7 or fewer Asian-Americans among 12 jurors.P(x≤7)=P(x≤7)=
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of heads in each outcome. For example, if the outcome is ttt, then R(ttt) = 0. Suppose that the random variable X is defined in terms of R as follows: X= 2R- 4R-4. The values of X are given in the table below. Outcome ttt tth hht thh tht hhh htthth Value of X -4 -6 -4 -4 -6 -4 Calculate the values of the probability distribution function of X, i.e. the function py. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X Px (x) olo

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