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2. Hexamethylbenzene undergoes free-radical chlorination to give one monochlorinated product (C₁2H17C1) and four dichlorinated products (C12H16C12). These products are easily separated by GC-MS, but the dechlorinated products are difficult to distinguish by their mass spectra. Draw the monochlorinated product and the four dichlorinated products, and explain how ¹3C NMR would easily distinguish among these compounds. (6 pts) Cl₂/hv Ch/v monochlorinated product dichlorinated products CI

2. Hexamethylbenzene undergoes free-radical chlorination to give one monochlorinated product (C₁2H17C1) and four dichlorinated products (C12H16C12). These products are easily separated by GC-MS, but the dechlorinated products are difficult to distinguish by their mass spectra. Draw the monochlorinated product and the four dichlorinated products, and explain how ¹3C NMR would easily distinguish among these compounds. (6 pts) Cl₂/hv Ch/v monochlorinated product dichlorinated products CI

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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2. Hexamethylbenzene undergoes free-radical chlorination to give one monochlorinated product (C₁2H17C1) and four dichlorinated products (C12H16C12). These products are easily separated by GC-MS, but the dechlorinated products are difficult to distinguish by their mass spectra. Draw the monochlorinated product and the four dichlorinated products, and explain how ¹3C NMR would easily distinguish among these compounds. (6 pts) Cl₂/hv Ch/v monochlorinated product dichlorinated products CI
Transcribed Image Text:2. Hexamethylbenzene undergoes free-radical chlorination to give one monochlorinated product (C₁2H17C1) and four dichlorinated products (C12H16C12). These products are easily separated by GC-MS, but the dechlorinated products are difficult to distinguish by their mass spectra. Draw the monochlorinated product and the four dichlorinated products, and explain how ¹3C NMR would easily distinguish among these compounds. (6 pts) Cl₂/hv Ch/v monochlorinated product dichlorinated products CI
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