2. Given the following reactions: 2 H20 +2 H2 + O2 AH = 480 kJ 2 HNO3 N2O5 + H20 AH = 85 kJ HNO3 → 1/2 N2 + 3/2 O2 + 1/2 H2 AH = -375 kJ Calculate AH for the reaction: N2O5 → N2 + 5/2 O2

Chemistry
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Chapter1: Chemical Foundations
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### Given Reactions and Enthalpy Changes

1. **Reaction:** \( 2 \text{H}_2\text{O} \rightarrow 2 \text{H}_2 + \text{O}_2 \)
   - **Enthalpy Change (\( \Delta H \)):** 480 kJ

2. **Reaction:** \( 2 \text{HNO}_3 \rightarrow \text{N}_2\text{O}_5 + \text{H}_2\text{O} \)
   - **Enthalpy Change (\( \Delta H \)):** 85 kJ

3. **Reaction:** \( \text{HNO}_3 \rightarrow \frac{1}{2} \text{N}_2 + \frac{3}{2} \text{O}_2 + \frac{1}{2} \text{H}_2 \)
   - **Enthalpy Change (\( \Delta H \)):** -375 kJ

### Task

Calculate \( \Delta H \) for the reaction: 
\[ \text{N}_2\text{O}_5 \rightarrow \text{N}_2 + \frac{5}{2} \text{O}_2 \]
Transcribed Image Text:### Given Reactions and Enthalpy Changes 1. **Reaction:** \( 2 \text{H}_2\text{O} \rightarrow 2 \text{H}_2 + \text{O}_2 \) - **Enthalpy Change (\( \Delta H \)):** 480 kJ 2. **Reaction:** \( 2 \text{HNO}_3 \rightarrow \text{N}_2\text{O}_5 + \text{H}_2\text{O} \) - **Enthalpy Change (\( \Delta H \)):** 85 kJ 3. **Reaction:** \( \text{HNO}_3 \rightarrow \frac{1}{2} \text{N}_2 + \frac{3}{2} \text{O}_2 + \frac{1}{2} \text{H}_2 \) - **Enthalpy Change (\( \Delta H \)):** -375 kJ ### Task Calculate \( \Delta H \) for the reaction: \[ \text{N}_2\text{O}_5 \rightarrow \text{N}_2 + \frac{5}{2} \text{O}_2 \]
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