(AT (hot)) = (Tf - Ti(hot)) MH20 CH20 (AT (cold)) 9cw = qcw should be a positive quantity since final temperature is higher than initial temperature (AT (cold) ) = (Tf - Ti(cold)) -qhw = 9cw+qcal qcal = (9hw +9cw) Ccal = acal/(AT (cold))
(AT (hot)) = (Tf - Ti(hot)) MH20 CH20 (AT (cold)) 9cw = qcw should be a positive quantity since final temperature is higher than initial temperature (AT (cold) ) = (Tf - Ti(cold)) -qhw = 9cw+qcal qcal = (9hw +9cw) Ccal = acal/(AT (cold))
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Using the following information solve for qhw, qcw, qcal and Ccal. Please show work!
Transcribed Image Text:4:48
final temperature is lower than initial
temperature
(AT (hot)) = ( Tf - Ti(hot))
qcw = MH₂0 CH₂0 (AT (cold))
qcw should be a positive quantity since
final temperature is higher than initial
temperature
(AT (cold) ) = ( Tf — Ti(cold) )
-qhw= 9cw+qcal
qhw +9cw)
Ccal =qcal/(AT (cold) )
qcal=-
To understand how the method of
calorimetry is used to calculate enthalpy
of neutralization, consider the following
experiment for the neutralization of HCI
(aq) with NaOH (aq)
HCl (aq) + NaOH (aq) → NaCl (aq) + H₂O (1)
The heat capacity for the calorimeter cup
is given as 6.80 J/K. In the experiment, 50
mL (50 g, assume a density of 1.0 g/mL)
of 1.00 M HCI solution is placed in the
calorimeter and allowed to equilibrate to
Transcribed Image Text:Volume of Cold water (ml):
Volume of Hot water (ml):
Ti(cold), probe (°C):
Ti(cold), thermometer (°C):
Ti(hot), (°C) initial:
Ti(hot) (°C), 30s:
Ti(hot) (°C), 60s:
Ti(hot) (°C), 90s:
Ti(hot) (°C), 120s:
Ti(hot)corr., °C, 120s
Tf (°C):
AT (hot) (°C or K):
AT (cold) (°C or K):
9hw (J):
50.00mL
50.00mL
22.77*C
24.50*C
38.2*C
37.20*C
37.00*C
36.80*C
36.60*C
34.8*C
29.09*C
-4.910
6.32 d
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