2. Given the following information, determine the load acting on a typical floor joist using ASD. The joists span 20 ft and are spaced 3 ft on center. Select the lightest K-series joist from the ASD joist selection tables. For a floor joist, the deflection limit is L/360. In addition to the series designation, also indicate the capacity of the joists. Dead Load: 28 psf Floor Live Load: 100 psf
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- Which of the following best gives the purlin load wuy? See loaded purlin. The figure shown has trusses 6m apart with midpoint sag rods and Purlins C150x12.5 spaced 2.5m on center. The roof truss is inclined 1 vertical to 2 horizontal. The weight of roofing materials is 0.9 kPa (includes self wt.), wind load is 0.8 kPa perpendicular to the roof surface, minimum roof live load is 0.6 kPa. Consider the roofing to provide full lateral support of the purlins. Fy = 345 mPa. Use the NSCP 2015 specifications. 2. 5m 2.5m 2. 5m roofing TRUSS TOP CHORD Wuy, Truss Spacing = 6m Wux 1 Purlins C150x12.5 Purlin Load Wt kN/m mm^2 mm C150x12.5 0.12 11400 12.7 152 5.1 d tw by SECTION Ix Sx rx ly sy Zy ry Zx mm mm mm^4 mm^3 mm mm^4 mm^3 mm mm^3 mm^3 mm mm 48 8.7 143 1100 112 48.4 378 65.2 1230 574 O 4.35 kN/m 5.56 kN/m O 25.02 kN.mWhich of the following best gives the purlin load wuy? See loaded purlin. The figure shown has trusses 6m apart with midpoint sag rods and Purlins C150x12.5 spaced 2.5m on center. The roof truss is inclined 1 vertical to 2 horizontal. The weight of roofing materials is 0.9 kPa (includes self wt.), wind load is 0.8 kPa perpendicular to the roof surface, minimum roof live load is 0.6 kPa. Consider the roofing to provide full lateral support of the purlins. F, = 345 mPa. Use the NSCP 2015 specifications. 2. 5m 2.5m 2. 5m roofing Wuy TRUSS TOP CHORD Truss Spacing = 6m Wux Purlins C150x12.5 Purlin Load Wt A kN/m mm^2 mm C150x12.5 0.12 11400 12.7 152 5.1 SECTION dtw by Ix Sx rx ly mm mm^4 mm^3 mm mm^4 mm^3 mm mm^3 mm^3 48 8.7 143 1100 112 48.4 378 65.2 1230 574 Sy ry Zx| Zy mm mm mm O 4.35 kN/m 5.56 kN/m O 25.02 kN.mA fully restrained beam shown, Find the deflection at midspan? 3/1 1/2 W%2 + t | Wo Wo-
- Wood planks are used on each working level. The deck width/bearer span is 5 ft.. The bearers and posts are standard pipe and the pipe material is A36 steel with a yield stress of 36,000 psi and modulus of elasticity of 29,000,000 psi. Bearers are to be located at a vertical spacing of 10 ft (largest, lowest post height). Posts are to be 7 ft oc (plank length) parallel to the building wall and 5 ft apart (bearer length) perpendicular to the building wall. There are four working levels and the anticipated scaffold loading will be med duty. A. Assuming the ultimate bending strength of the planks is 3,800 psi (apply a 4:1 F.O.S.), determine the required minimum plank thickness to the nearest 100th. B. Based on the bearer material provided, what is the minimum pipe size that can be safely used? See Appendix 2 in your textbook for steel pipe properties. C. Based on the post material provided, can a 2” standard pipe be used safely? Be sure it satisfies buckling stress conditions only.Question 1 Check that the medium-term load of 38 kN applied to the spaced column shown in below complies with the design requirements of BS 5268-2. The column consists of two 38 x 150 C22 timbers 76 mm apart. All joints are glued and intermediate packs are 250 mm long. suitable connection #### x ->89² 6:38. Y T -end blocking AP 100 intermediate blocking L₂ 1₁ x W L W EFH 400 m 38kN medium term load -ICHICHID -200 600 600 600 600 600 600 200 38kN medium term loadPrepare the Bar bending schedule of a simply supported R.C.C. Lintels from the following specification: Size of lintel 300mm widex 200mm depth. Main bars in tension zone of Fe 250(grade I) 3 bars of 16mm dia., one bar is cranked through 45 degree at 170 mm from each end 2 No. anchor bars at top 8mm dia. Two legged stirrups@150mm c/c of 6mm dia. through out. Clear span of the lintel is 1150mm. Bearing on either side is 150mm
- ure B 2m2 m C -2 m D 4 m 500 N 700 N 2 of 2 Part B Identify the zero-force members in the truss shown in (Figure 2). Check all that apply. 000 CD DE CG CF FG BC BG DF AG EF AB Submit Provide Feedback Request AnswerO 88 130% v - + I Annotate T| Edit Trial expired Unlock Full Version ENGR 263 + A A A T O 4.10 Member AB is the beam under consideration. As shown in the illustration of the loading condition, member AB is an overhanging beam that supports a uniformly distributed roof load of 500 lb/ft. It also carries concentrated loads from a rooftop HVAC unit (4000 lb), an interior hanging display support (2000 lb), and a marquee sign (3000 lb). Marquee overnang Displau SLIPPort II Raof Kiots Ol I W = 500 Ib/Ft A B 4000 b 2000 000 I Steel beam !! I1 3 FE 5 FE - Ft RoOFtop HVAC unit 10 FE 4 Ft Marquee sign< R R2 Steel beam (negligible weight) Free-body diagram Dispiay Support Loading conditionPrepare the Bar bending schedule of a simply supported R.C.C. Lintels from the following specification:Size of lintel 300mm wide x 200mm depth. Main bars in tension zone of Fe250(grade I) 3 bars of 16mm dia., one bar is cranked through 450 at 170 mm from each end2 No. anchor bars at top 8mm dia.Two legged stirrups@150mm c/c of 6mm dia. throughout.Clear span of the lintel is 1150mm.Bearing on either side is 150mm
- 2010-biT REINTORCED CONCHSTE Homework3 Design the Inverted T-beam shown in the following floor system for both positive and negative moments, then druw the detailing showing the top and bottom reinforcing sleel bars • The columns are masonry construction Additional Dead Load (Superimposed DL) - 2.5 KN/m Live Load: 4 kNm Slab Thickness : 150 mm f21 MPa , ty 420 MPa 3.0m of 9.0m 3.3m 40m 4.0m Ao 4.0pm 4.0m 40m SECTION 1-1 CRY 407 ENGINEERING DEPARTMENTThe largest load P that can be applied is approximately equals: Arca - 0.00126 m oall - 45 MPa a)57 kN B Aren- 0.0007 m b)60 kN Weld allowable strength - 60 kN all - 95 MPa c)67 kN d)50 kNIn the design calculation for purin, assume self-weight of the cladding is 0.05 kpa and self-weight of the purlin is 0.1 kpa. If the external wind pressure is -3.0 kpa, internal wind pressure is 1.0 kpa or -0.5 kPa, then the ultimate limit load combination for purlin is?