2. Given that 1 0 2 -1 0 [A – 31|0] = | -2 1 RREF 0 0 find an eigenvector that corresponds to the eigenvalue A = 3, by solving the system (А — 31)х — Ө. 3. Given that 1 1 0 0 0 0 1 1 0 [A – 01 | 0] = RREF 2 2 0 find an eigenvector that corresponds to the eigenvalue A = 0, by solving the system (А - 01)х — 0. %3D
2. Given that 1 0 2 -1 0 [A – 31|0] = | -2 1 RREF 0 0 find an eigenvector that corresponds to the eigenvalue A = 3, by solving the system (А — 31)х — Ө. 3. Given that 1 1 0 0 0 0 1 1 0 [A – 01 | 0] = RREF 2 2 0 find an eigenvector that corresponds to the eigenvalue A = 0, by solving the system (А - 01)х — 0. %3D
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter5: Linear Inequalities
Section5.2: Solving Inequalities By Multiplication And Division
Problem 3AGP
Related questions
Question
Consider the 2X2 matrix (picture included)
1. Suppose that det(A −λI) = λ(λ −3). What are the eigenvalues of the matrix A?
and part 2 and 3 (picture included)

Transcribed Image Text:1 1
2 2
A =
![2. Given that
1 0
2 -1 0
[A – 31|0] = |
-2
1
RREF
0 0
find an eigenvector that corresponds to the eigenvalue A =
3, by solving the system
(А — 31)х — Ө.
3. Given that
1 1 0
0 0 0
1 1 0
[A – 01 | 0] =
RREF
2 2 0
find an eigenvector that corresponds to the eigenvalue A = 0, by solving the system
(А - 01)х — 0.
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b41904f-5f6c-41e1-9022-6df3fa5c7790%2F982821d9-e7c6-40b0-a06b-46f2105e0a14%2Fz50fqr_processed.png&w=3840&q=75)
Transcribed Image Text:2. Given that
1 0
2 -1 0
[A – 31|0] = |
-2
1
RREF
0 0
find an eigenvector that corresponds to the eigenvalue A =
3, by solving the system
(А — 31)х — Ө.
3. Given that
1 1 0
0 0 0
1 1 0
[A – 01 | 0] =
RREF
2 2 0
find an eigenvector that corresponds to the eigenvalue A = 0, by solving the system
(А - 01)х — 0.
%3D
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