2. Given in the accompanying tabulation are the adjusted latitudes and departures for a property survey. Determine the adjusted length and adjusted bearing of each course. Tabulate all given data and computed values accordingly. Course Adjusted Latitude Adjusted Departure +N -S +E -W 1-2 103.82 117.09 2-3 3.67 176.83 3-4 166.64 20.34 4-5 27.65 224.05 5-1 86.80 90.21 Sums +194.29 -194.29 +314.26 -314.26

2. Given in the accompanying tabulation are the adjusted latitudes and departures for a property survey. Determine the adjusted length and adjusted bearing of each course. Tabulate all given data and computed values accordingly. Course Adjusted Latitude Adjusted Departure +N -S +E -W 1-2 103.82 117.09 2-3 3.67 176.83 3-4 166.64 20.34 4-5 27.65 224.05 5-1 86.80 90.21 Sums +194.29 -194.29 +314.26 -314.26

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A parcel of land has been surveyed in the field and the lengths and bearings of the various sides are shown: a. Compute the error of closure for the traverse. b. Compute the precision of linear measurement. Determine the included area (using DPD method) within the traverse in acres. LINES AB BC CD DA BEARINGS N53' 27' E $ 66' 54'E $ 29'03' W N 52'00' W T DISTANCES (m) 59.82 70.38 76.62 95.75
3. AREA BY DPD. In the accompanying tabulations are the adjusted latitudes and adjusted departures of two traverse. By employing the double parallel distance method, determine the area (in sq.m. and ha.) of each traverse. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S +E -w AB 420.75 713.84 BC 296.08 693.05 CD 894.37 405.36 DE 501.25 926.54 EF 386.42 695.04 FA 884.53 190.67 Sums +1691.70 F1691.70 181 2.25 1812.25 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N +E 1-2 299.30 295.58 2-3 338.05 223.56 24.52 245.77 381,36 230.52 4-5 8.05 5-6 463.09 6 - 1 626.11 309. 87 Sums +949.93 -949.93 + 772.96 -772.96
Compute the area of the given traverse using DPD and DMD method. POINT NORTH/SOUTH DEGREES MINUTES EAST/WEST DISTANCE (M) 0-1 19 21 E 530.49 1-2 81 21 23.59 2-3 N 10 45 E 108.31 3-4 N 15 6 E 30.47 4-5 S 77 26 E 29.95 5-6 23 120.29 6-7 S 23 17.61 7-8 81 21 10.08 8-1 N 81 21 23.42
AREA BY DPD. In the accompanying tabulations are the adjusted latitudes and adjusted departures of two traverse. By employing the double parallel distance method, determine the area (in sq.m. and ha.) of each traverse. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +N -S +E -W AB 420.75 713.84 BC 296.08 693.05 CD DE 894.37 405.36 501.25 926.54 EF 386.42 695.04 FA 884.53 190.67 Sums +1691.70 -1691.70 +1812.25 1812.25 ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N -S +E -W |-2 299.30 295.58 223.56 245.77 2-3 338.05 3-4 24.52 8.05 381,36 230.52 4-5 463.09 5-6 6 - 1 626. 11 309. 87 Sums +949.93 -949.93 +772.96 -772.96
Given the following adjusted latitudes and adjusted departures of a closed traverse, determine the area of the traverse by the coordinate method. Assume that the origin of the coordinate system passes thru station 1. Show your solution. * ADJUSTED ADJUSTED LINE LATITUDE DEPARTURE (+) N (-) S (+) E (-) W 1-2 665.71 222.27 2-3 762.12 783.89 3-4 502.41 961.78 4-5 1177.76 393.32 5-6 297.67 1466.62 6-1 550.01 894.64 SUMS
For the given set of adjusted latitudes and adjusted departures shown in the accompanying tabulation, determine the area of the traverse (in sq. m. and ha.) using the double parallel method. ADJUSTED LATITUDE ADJUSTED DEPARTURE COURSE +N -S +E -W 1 - 2 281.28 281.06 449.32 2 - 3 168.75 337.56 281.22 3-4 450.66 112.50 4 - 5 450.03 225.08 5 - 6 335.86 6 - 1 450.06 +1011.60m -1,011.60 m +900.09 m -900.09 m Sums
. Problem 1 Compute the area within the following traverse using the Coordinate method and CHECK by the DMDS method Balanced Coordinates Course Dep Lat Point X Y AB -226.9846 98.7106 A 709,489.434 709,262.449 709,176.011 709,061.165 709,361.616 708,846.452 G 709,568.788 709,682.105 I 709,563.827 121,072.089 121,170.800 120,992.637 120,797.489 120,807.032 120,287.159 120,244.663 119,715.939 120,610.402 BC -86.4386 -178.1623 CD -114.8457 -195.1486 C DE 300.4512 9.5436 EF -515.1646 -519.8733 日 FG 722.3360 -42.4958 F GH 113.3175 -528.7245 HI -118.2782 894.4631 IA -74.3929 461.6870
Given in the following tabulation are the observed data for a transverse obtained from a transit-tape survey. Using Double Meridian Method (DMD) determine the area of the lot and divide the lot into two(2) equal parts with a dividing line that passes through point B. (Tabulated your answer) Course Length (m) Azimuth from South AB 495.85 52⁰ 30’ BC 850.62 47⁰ 02’ CD 855.46 112⁰ 22’ DE 1020.87 167⁰ 35’ EF 1117.26 262⁰ 44’ FA 960.08 305⁰ 51’
Q.4. Compute by DMDs the area in hectares within a closed-polygon traverse ABCDEFA by placing the X and Y axes through the most southerly and most westerly stations, respectively. Departures and latitudes (in meters) follow. AB: E dep. 30, N lat. = 40; BC: E dep. = 70, N lat. = 10; CD = E dep. = 30, S lat = 50; DE: W dep = 60, S lat. = 40; EF: W dep = 90, S lat = 30; FA: E dep. = 20, N lat = 70.
AREA BY DMD. For the given sets of adjusted latitudes and adjusted departures shown in the accompanying tabulations, determine the area of each traverse (in sq.m. and ha.) using the double meridian distance method. ADJUSTED LATITUDE ADJUSTED DEPARTURE LINE +E AB 715.20 1200.53 BC CD DE 414.29 401.78 1735.58 419.88 200.70 1606.43 EF 617.59 456.66 FG 849.91 202.83 GA 233.53 677.83 Sums +2383.40 -2383.40 +2482.97 -2482.97
2) A surveyor sets up a transit at P which is located in the middle portion of a four- sided tract of land and reads directions and measures distances, as given below, to the five corners. Find the area of the tract, in square meters. LINE BEARING DISTANCE N 41030' W Ν 38010, Ε S 70°20' E S 60°15' W AP 410.52 m ВР 532.18 m CP 450.75 m DP 590.08 m
1. Below is a transit and tape survey notes of a lot, compute the following: a. Balance the latitudes and departures using transit rule. b. Linear error of closure of the traverse, its distance, bearing and relative precision. C. Area of the lot by DMD method in hectares. d. Plot the traverse. Deflection angle 1-2 N 10° E 55° 31 R 650 m 99° 31' R 895 m 44° 01 R 315 m 92° 01' R 875 m 68° 56 R Bearin STA Line Dist 1 2 2-3 3 3-4 4 4-5 5 5-1 410 m