Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:### Reaction Problem
**Given Reaction:**
Start with benzoic acid (\( \text{C}_6\text{H}_5\text{COOH} \)).
1. **Reagent 1:** \( \text{SOCl}_2 \) (Thionyl chloride)
2. **Reagent 2:** \( 2 \text{CH}_3\text{NH}_2 \) (Methylamine)
**Steps of Reaction:**
1. **Conversion to Acid Chloride:**
- Benzoic acid reacts with \( \text{SOCl}_2 \), converting the carboxylic acid group (\(-\text{COOH}\)) into an acyl chloride group (\(-\text{COCl}\)).
- The product is benzoyl chloride (\( \text{C}_6\text{H}_5\text{COCl} \)).
2. **Formation of an Amide:**
- Benzoyl chloride reacts with excess methylamine (\( \text{CH}_3\text{NH}_2 \)).
- The acyl chloride group is converted into an amide group, forming N-methylbenzamide (\( \text{C}_6\text{H}_5\text{CONHCH}_3 \)).
**Expected Product:**
- **N-methylbenzamide** (\( \text{C}_6\text{H}_5\text{CONHCH}_3 \))
This reaction sequence illustrates the transformation of a carboxylic acid to an acyl chloride and then to an amide, a common pathway in organic synthesis for modifying the carboxylic acid functional group.
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