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2. From a mole balance of the gas-phase reactor below, the following expression is obtained for dCA/dt, dCB/dt, and dCc/dt. The density, volume, and temperature are constant. 2A-B (-rAKICA) BC (-1B K2CB) - k₁CA V dCA F(CAL-CA) = dt dCB -F g=g=g|= dt dt = V -F -CB + 0.5k₁CA - k₂CB - Cc + k₂CB³ Fi. CAL V ☐ F. CA. CR.CC (a) What is the value of CB at steady-state (your answer must be simplified)? (b) List the states, inputs, and parameters for the system.

2. From a mole balance of the gas-phase reactor below, the following expression is obtained for dCA/dt, dCB/dt, and dCc/dt. The density, volume, and temperature are constant. 2A-B (-rAKICA) BC (-1B K2CB) - k₁CA V dCA F(CAL-CA) = dt dCB -F g=g=g|= dt dt = V -F -CB + 0.5k₁CA - k₂CB - Cc + k₂CB³ Fi. CAL V ☐ F. CA. CR.CC (a) What is the value of CB at steady-state (your answer must be simplified)? (b) List the states, inputs, and parameters for the system.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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2. From a mole balance of the gas-phase reactor below, the following expression is obtained for dCA/dt, dCB/dt, and dCc/dt. The density, volume, and temperature are constant. 2A-B (-rAKICA) BC (-1B K2CB) - k₁CA V dCA F(CAL-CA) = dt dCB -F g=g=g|= dt dt = V -F -CB + 0.5k₁CA - k₂CB - Cc + k₂CB³ Fi. CAL V ☐ F. CA. CR.CC (a) What is the value of CB at steady-state (your answer must be simplified)? (b) List the states, inputs, and parameters for the system.
Transcribed Image Text:2. From a mole balance of the gas-phase reactor below, the following expression is obtained for dCA/dt, dCB/dt, and dCc/dt. The density, volume, and temperature are constant. 2A-B (-rAKICA) BC (-1B K2CB) - k₁CA V dCA F(CAL-CA) = dt dCB -F g=g=g|= dt dt = V -F -CB + 0.5k₁CA - k₂CB - Cc + k₂CB³ Fi. CAL V ☐ F. CA. CR.CC (a) What is the value of CB at steady-state (your answer must be simplified)? (b) List the states, inputs, and parameters for the system.
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