2. For example: 1. Create an ER model for each of the following descriptions: (a) Each Company operates four Departments, and each Department belongs to one Company. (b) Each Department in part(a) employs one or more Employees, and each Employee works for one Department with a startdate. (c) Each of the Employees in part (b) may or may not have one or more Dependents, and each Dependent belongs to one Employee. (d) suppose: Company with attributes cnumber, cname, caddress, President. Department with attributes dname, dnumber, location. Employee with attributes ename, ssn(for social security number), Sex, address, salary, birthdate. Dependent with attributes dpName, Sex, birthdate, and relationship (to the employee). (e) Represent all the ER diagrams described in (a), (b), (c) and (d) as a single ER diagram. 2. Create an logical data model for relational database of the above designed ER model. Note:1) An logical data model is collection of relational schemas; 2) A relational schema is : tablename(attributename1, attributename2,..., attributenameN).

2. For example: 1. Create an ER model for each of the following descriptions: (a) Each Company operates four Departments, and each Department belongs to one Company. (b) Each Department in part(a) employs one or more Employees, and each Employee works for one Department with a startdate. (c) Each of the Employees in part (b) may or may not have one or more Dependents, and each Dependent belongs to one Employee. (d) suppose: Company with attributes cnumber, cname, caddress, President. Department with attributes dname, dnumber, location. Employee with attributes ename, ssn(for social security number), Sex, address, salary, birthdate. Dependent with attributes dpName, Sex, birthdate, and relationship (to the employee). (e) Represent all the ER diagrams described in (a), (b), (c) and (d) as a single ER diagram. 2. Create an logical data model for relational database of the above designed ER model. Note:1) An logical data model is collection of relational schemas; 2) A relational schema is : tablename(attributename1, attributename2,..., attributenameN).

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Task 6: The Car Maintenance team considered that the available maintenance tasks should also have the price information in the database. Alter the MAINTENANCE_TYPES table to include a new column named MAINTENANCE_PRICE of type FLOAT. ANSWER IN MYSQL PLEASE
Create a SQL statement to Add a CHECK constraint for the CTYPE column in the CLIENTS table. It must accept either New or Old only.
Using the Categories, Subjects, and Classes tables, list the category description, SubjectID, SubjectCode, and SubjectName for all subject that are taught on Wednesdays. Do not list any subject more than once.
Display the name of customer 16 and the names of all the customers that are in the same zip code as customer 16. (Be sure this query will work for any customer.) Rewrite your answer to Problem for each customer, not just customer 16.
What did you take away from the process of creating your religion characteristics table?
database join exercises
Generate the table creation DDL for the schema. Consider the keysprimary and foreign.
Write a select statement for the following: Join all the tables of the lunches database together (Anything table starting with L_). Show all the columns of each table. To do this, modify the select statement in this section and add the three other tables to it. How many rows and columns are in this table?
Task 5:The marketing team wants to celebrate the success of StayWell with a party. The team wants a table with the names of all residents and owners combined into single column named PARTICIPANT. You need to combine this information from the tables and send it back to the team. You do not need to create a new table in the database schema. I found the answer but it wroten on paper so its really hard to understand what it is, that's why I am posting this question again.
JOIN TABLES One row in the PAT_ENC table represents one patient encounter. One row in the ORDER MED table represents one medication order. One patient encounter can have many medication orders but one medication order can only have one patient encounter. In other words, the cardinality of this PAT_ENC to ORDER_MED relationship is one-to- many. You start a query with PAT_ENC. You then add ORDER_MED using an inner join. What is true about the granularity of the result set before and after adding the ORDER_MED table? SELECT ONE OF THE FOLLOWING A. The granularity stays at one row per patient encounter. B. The granularity stays at one row per medication order. C. The granularity changes from one row per patient encounter to one row per medication order on an encounter. D. The granularity changes from one row per medication order to one row per patient encounter.
Find the names of the pilots who are not certified to fly the aircrafts in the flight table. Sort the name by ascending order.
Open the Missing Addresses query in Design view. Add a new column to determine if a customer does not have an address on file. If the customer’s Address is null, it should display Missing. If not, it should display nothing. Name the column AddressPresent. Add criteria of Missing to the column you just created, so only the customers missing an address display. Move the AddressPresent field so it appears between PhoneNumber and Address. Run the query. Ensure only customers with null Address fields display. Save and close the query.