Provide an example of a 3 table OUTER join. Explain how it works and what the order of of the joins is.
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Provide an example of a 3 table OUTER join. Explain how it works and what the order of of the joins is.
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- Access path A database table is composed of records and fields hold data. Data is stored in records. A field is a part of a record and contains a single piece of data for the subject of the record. The access path for finding the list of books is AUTHOR: AuthorID, Lname BOOKAUTHOR: AuthorID, ISBN BOOKS: Pubdate, ISBNWhen working with a relational database, a select operation may be used to reduce the amount of space used by a table by removing columns that meet certain requirements.Is this the right answer or the wrong answer?Normalization works through a series of stages called normal forms. For most purposes in business database design, the normalization process. stages are as high as you need to go in five two four three
- In a relational database, a select operation reduces the size of a table by removing columns that meet certain requirements.Is it accurate or inaccurate?true/false INNER JOIN combines two relations. It takes the second relation, and appends it to the end of the first relation. In Corelated Subqueries, subquery is executed independent of the outer query: subquery is executed only once. SELECT * FROM sys.Relations displays information about all the user-defined relations within a database. Given GENDER and STUDENT relations, SELECT Gender, FName, LName FROM GENDER LEFT OUTER JOIN STUDENT ON STUDENT.GenderCode = GENDER.GenderCode ≡ SELECT Gender,FName, LName FROM STUDENT RIGHT OUTER JOIN GENDER ON STUDENT.GenderCode = GENDER.GenderCode The statements select RIGHT('I wish I had attended the practice hours', 9) and select…True or false: The database management system can protect you in a number of ways from getting invalidated into the database in the first place through a series of rules called "referential constraints". Sometimes they are implemented through a new related data table.
- In a relational database, the number of columns in a table that are able to satisfy the constraints that have been defined may be decreased by the use of an operation called select. Which is it: the right answer or the erroneous answer?In a relational database, the number of columns in a table that are able to satisfy the constraints that have been defined may be decreased by the use of an operation called select.Which is it: the right answer or the erroneous answer?In a relational database, a select operation is used to minimise the size of a table by eliminating columns that fulfil certain criteria.Is this the right answer or the wrong answer?
- Database Schema The schema for the Ch07_FACT database is shown below and should be used to answer the next several problems. Click this image to view it in its own tab. FIGURE P7.56 THE CH07_FACT ERD CHECKOUT PATRON PK Check Num PK Pat ID FK1 Book_Num FK2 Pat_ID Check_Out_Date Check_Due_Date Check_In_Date >0-----H- Pat_FName Pat LName Pat_Type BOOK AUTHOR PK Book_Num PK Au ID Book_Title Book_Year Book_Cost Book_Subject FK1 Pat_ID Au_FName Au_LName Au_BirthYear WRITES PK,FK1 Book Num PK,FK2 Au ID The CIS Department at Tiny College maintains the Free Access to Current Technology (FACT) library of e-books. FACT is a collection of current technology e-books for use by faculty and students. Agreements with the publishers allow patrons to electronically check out a book,Indexing Consider a relational database that consists of the relational tables created by the following CREATE TABLE statements: CREATE TABLE PART( P_PARTKEY NUMBER(12) NOT NULL, P_NAME VARCHAR(55) NOT NULL, P_RETAILPRICE NUMBER(12,2) NOT NULL, CONSTRAINT PART_PEKEY PRIMARY KEY (P_PARTKEY) ); CREATE TABLE SUPPLIER( S_SUPPKEY NUMBER(12) NOT NULL, S_NAME CHAR(25) NOT NULL S_NATIONKEY NUMBER(12) NOT NULL, S_PHONE CHAR(15) NOT NULL, CONSTRAINT SUPPLIER_PKEY PRIMARY KEY (S_SUPPKEY) ); CREATE TABLE PARTSUPP( PS_PARTKEY NUMBER(12) NOT NULL, PS_SUPPKEY NUMBER(12) NOT NULL, PS_SUPPLYCOST NUMBER(12,2) NOT NULL, CONSTRAINT PARTSUPP_PKEY PRIMARY KEY (PS_PARTKEY, PS_SUPPKEY), CONSTRAINT PARTSUPP_FKEY1 FOREIGN KEY (PS_PARTKEY) REFERENCES PART(P_PARTKEY), CONSTRAINT PARTSUPP_FKEY2 FOREIGN KEY (PS_SUPPKEY) REFERENCES SUPPLIER(S_SUPPKEY) ); Determine what index should be created to improve the performance of the queries listed below in the best possible way. Consider each one of the…In a relational database, a select operation is used to minimise the size of a table by eliminating columns that do not fulfil certain constraints.Is this statement true or false?