2. For each of the four trials, (a) Find the period of the airplane's motion, which we will call T. (F;sine)7 (b) Find the airplane's mass from Eqn. (2) m = In Eqn. (2) r is the radius of the circular path
2. For each of the four trials, (a) Find the period of the airplane's motion, which we will call T. (F;sine)7 (b) Find the airplane's mass from Eqn. (2) m = In Eqn. (2) r is the radius of the circular path
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
Transcribed Image Text:2. For each of the four trials,
(a) Find the period of the airplane's motion, which we will call T.
(F;sine) T?
(b) Find the airplane's mass from
Egn. (2)
m =
4nr
In Eqn. (2) r is the radius of the circular path
3. The masses of the airplane (as measured on a scale) are 0.2935 kg for trial 13B
0.2147
kg for trial 2 ; 0.3935 kg for trial 3 ; 0.2939 kg for trial 4.
4. (a) Find the percent difference between each of masses given in step 3 above and the
corresponding mass calculated using Eqn. (1).
(b) Find the percent difference between each of masses given in step 3 above and the
corresponding mass calculated using Eqn. (2).
Transcribed Image Text:Trial
Diameter of
Tension in
Angle of
String
Time for Two
Airplane's Path
String
Revolutions
1
90.5 cm
4.5 N
52
2.5000 sec
104.5 cm
7.5
74
1.7333 sec
87.4 cm
6.5
52
2.3917 sec
4
83.5 cm
5.2
50
2.3250 sec
Diameter for trial 1 is: 75.5 sin (52) = (45.31) (2) = 90.5 cm
Diameter for trial 2 is: 54.5 sin (74) = (52.39) (2) = 104.5 cm
Diameter for trial 3 is: 55.5 sin (52) = (43.73) (2) = 87.4 cm
Diameter for trial 4 is: 54.5 sin (50) = (41.75) (2) = 83.5 cm
Expert Solution
Step 1
3a)
Time period is time for 1 revolution.
| Trial | Time for two revolutions | Time period |
| 1 | 2.5000 sec | 2.5000/2 = 1.2500 sec |
| 2 | 1.7333 sec | 1.7333/2 = 0.8667 sec |
| 3 | 2.3917 sec | 2.3917/2 = 1.1958 sec |
| 4 | 2.3250 sec | 2.3250/2 = 1.1625 sec |
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