2. For any n E N, let G, denote the interval (-). Prove that each G, is an open set in R and each G, is not a closed set in R. Let G =N Gm. Lastly, explain why G is not an open set. (You are showing that an infinite intersection of open sets is not necessarily open.) Hint: For latter question, find all the elements in G.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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2. For any \( n \in \mathbb{N} \), let \( G_n \) denote the interval \( \left(-\frac{1}{n}, \frac{1}{n}\right) \). Prove that each \( G_n \) is an open set in \( \mathbb{R} \) and each \( G_n \) is not a closed set in \( \mathbb{R} \). Let

\[
G = \bigcap_{n=1}^{\infty} G_n.
\]

Lastly, explain why \( G \) is not an open set. (You are showing that an infinite intersection of open sets is not necessarily open.)

*Hint: For latter question, find all the elements in \( G \).*

---

This exercise explores the properties of open and closed sets in the context of real analysis, specifically focusing on the behavior of infinite intersections of open intervals.
Transcribed Image Text:2. For any \( n \in \mathbb{N} \), let \( G_n \) denote the interval \( \left(-\frac{1}{n}, \frac{1}{n}\right) \). Prove that each \( G_n \) is an open set in \( \mathbb{R} \) and each \( G_n \) is not a closed set in \( \mathbb{R} \). Let \[ G = \bigcap_{n=1}^{\infty} G_n. \] Lastly, explain why \( G \) is not an open set. (You are showing that an infinite intersection of open sets is not necessarily open.) *Hint: For latter question, find all the elements in \( G \).* --- This exercise explores the properties of open and closed sets in the context of real analysis, specifically focusing on the behavior of infinite intersections of open intervals.
Expert Solution
Step 1

Here Gn=-1n,1n

    so, G1=-1,1

          G2=(-12,12)

          ..

          Gn=-1n,1n

Since all Gn are Open intervals , so each Gn is open set in R. because every point is interior point.

Now, a set is said to be closed iff it contains all of  its limit points.

 set of limit point for each Gn=-1n,1n

      since  Gn does not contain its limit set.so, is not closed.

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