I need help understanding these 3 questions ChromeFileEditView HistoryBookmarksProfilesTabWindowHelpSun Oct 3 7:23 PMFSC myBb LEAMyBb MatВЬ МаBb HorBb WehttpBb LEABb MatADIEMH RecEMIH RecEMH RecG sho VerCor010Deei! Ver o Rec W VerOld+BbFSC Magus01Adeel 5 pt2.pdffarmingdale.open.suny.edu/bbcswebdav/pid-2228193-dt-content-rid-23286868_1/courses/202109-MTH245-001-90761/MTH%20245%20Dynamical%20Systems%20of%20Equations.pdfA1101AppsReading ListMTH 245 Dynamical Systems of Equations.pdf2 / 4+ | 0 O100%1011101TestDyaanical Syten af Linar Equations2. Find the value(s) of the parameter t for which the following system of linearequations has (a) unique solution, (b) no solution, and (c) infinitely manysolutions.12z = 1||2x+3у-z %3D8-a, la ..-42y+(r -2)z=t+2nshipACK.jpg3[1 0-21[1-21[1-2123-18331122t? -2t+22t2 - 2t+22t? - 2t+2|Screen Shot1-22021-10...1.54 AM→ |0112ization1? -4t- 2a. If t – 4 + 0 or t +±2, the system has a unique solution.3b. If t=-2, the system has no solution. Last row becomes [0 0 0 -4].izationJPGc. If t= 2, the system has infinitely many solutions (see graph below) since thelast row becomes 0 0 0 0.10050k.JPGOCTPAGESWP101......国II

The given equations are as x-2z=1 2x+3y-z= 8 2y+(t2-2)z= t+2 We have to find the value of t and…

2. Find the value(s) of the parameter t for which the following system of linear equations has (a) unique solution, (b) no solution, and (c) infinitely many solutions. x - 2z =1 2x+3y-z=8 2y+(r* -2)z =t+2 10 -2 1 2 3 0 2 -2 t+2] 1 0 -0 3 o 2 r-2 1+2 -2 -2 -1 6 lo 2 r-2 1+2] 1 0 -2 2 0 0 -4t-2 a. If -4 0 or t+ ±2, the system has a unique solution. b. If t=-2, the system has no solution. Last row becomes [0 o 0 -4). c. If t= 2, the system has infinitely many solutions (see graph below) since the last row becomes [0 o o o). 100 101

2. Find the value(s) of the parameter t for which the following system of linear equations has (a) unique solution, (b) no solution, and (c) infinitely many solutions. x - 2z =1 2x+3y-z=8 2y+(r* -2)z =t+2 10 -2 1 2 3 0 2 -2 t+2] 1 0 -0 3 o 2 r-2 1+2 -2 -2 -1 6 lo 2 r-2 1+2] 1 0 -2 2 0 0 -4t-2 a. If -4 0 or t+ ±2, the system has a unique solution. b. If t=-2, the system has no solution. Last row becomes [0 o 0 -4). c. If t= 2, the system has infinitely many solutions (see graph below) since the last row becomes [0 o o o). 100 101

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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I need help understanding these 3 questions

Chrome
File
Edit
View History
Bookmarks
Profiles
Tab
Window
Help
Sun Oct 3 7:23 PM
FSC my
Bb LEA
My
Bb Mat
ВЬ Ма
Bb Hor
Bb We
http
Bb LEA
Bb Mat
ADI
EMH Rec
EMIH Rec
EMH Rec
G sho Ver
Cor
010
Dee
i! Ver o Rec W Ver
Old
+
Bb
FSC Ma
gus
01
Adeel 5 pt2.pdf
farmingdale.open.suny.edu/bbcswebdav/pid-2228193-dt-content-rid-23286868_1/courses/202109-MTH245-001-90761/MTH%20245%20Dynamical%20Systems%20of%20Equations.pdf
A
1101
Apps
Reading List
MTH 245 Dynamical Systems of Equations.pdf
2 / 4
+ | 0 O
100%
101
1101Test
Dyaanical Syten af Linar Equations
2. Find the value(s) of the parameter t for which the following system of linear
equations has (a) unique solution, (b) no solution, and (c) infinitely many
solutions.
1
2z = 1
||
2x+3у-z %3D8
-
a, la ..-4
2y+(r -2)z=t+2
nship
ACK.jpg
3
[1 0
-2
1
[1
-2
1
[1
-2
1
2
3
-1
8
3
3
1
1
2
2
t? -2
t+2
2
t2 - 2
t+2
2
t? - 2
t+2|
Screen Shot
1
-2
2021-10...1.54 AM
→ |0
1
1
2
ization
1? -4
t- 2
a. If t – 4 + 0 or t +±2, the system has a unique solution.
3
b. If t=-2, the system has no solution. Last row becomes [0 0 0 -4].
ization
JPG
c. If t= 2, the system has infinitely many solutions (see graph below) since the
last row becomes 0 0 0 0.
100
50
k.JPG
OCT
PAGES
W
P
101
...
...
国
II

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